In the problem below, x and y are local application program values Read( ) and Write( ) fetch and stored the persistent values in a database, The database values are read / written by two different transactions. The time sequence of these operations is shown in the table below. You cannot change the time sequence. Take the initial values of x and y to be x = 4, y = 2. a) In this part the transactions are operating with isolation level READ UNCOMMITTED (no locks) Time | Transaction 1 Transaction 2 Read(y) y=y+5 Read(y) yy+ 10 3 Write(y) Read(x) 6. Read(x) X=x+ y: Write(y) 8. 10 Commit 11 Xx+y Write(y) Commit 12 13 For the execution order shown above, what are the final values of x and y? Answer: x=

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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In the problem below, x and y are local application program values Read( ) and Writel ) fetch and stored the
persistent values in a database. The database values are read / written by two different transactions. The time
sequence of these operations is shown in the table below. You cannot change the time sequence.
Take the initial values of x and y to be x = 4, y = 2.
a) In this nart the transactions are operating with isolation level READ UNCOMMITTED (no locks)
Time
Transaction 1
Transaction 2
Read(y)
y=y+5
2
Read(y)
y=y+ 10
3
4
Write(y)
Read(x)
7
Read(x)
8
X=x+ y:
Write(y)
Commit
9.
10
11
x=x+y
Write(y)
12
13
Commit
For the execution order shown above, what are the final values of x and y?
Answer: x=
b) There is a problem with the interleaved execution plan for these transactions.
What is the problem, i.e., which concurrency problem does this demonstrate?
Answer:
c) Rewrite the sequence of operations using the standard technique for dealing with concurrency
problems of this type for isolation level SERIALIZABLE. In the columns on the right specify
the type of requests made. (type your answer into the grid below) You cannot change the time sequence.
Time
Trans # Requests
Transaction 1
Transaction 2
1
2
3
4
5
6.
7
9
10
11
12
13
d) Was the concurrency problem completely solved? If not, what happened and what should be done next?
Answer:
Transcribed Image Text:In the problem below, x and y are local application program values Read( ) and Writel ) fetch and stored the persistent values in a database. The database values are read / written by two different transactions. The time sequence of these operations is shown in the table below. You cannot change the time sequence. Take the initial values of x and y to be x = 4, y = 2. a) In this nart the transactions are operating with isolation level READ UNCOMMITTED (no locks) Time Transaction 1 Transaction 2 Read(y) y=y+5 2 Read(y) y=y+ 10 3 4 Write(y) Read(x) 7 Read(x) 8 X=x+ y: Write(y) Commit 9. 10 11 x=x+y Write(y) 12 13 Commit For the execution order shown above, what are the final values of x and y? Answer: x= b) There is a problem with the interleaved execution plan for these transactions. What is the problem, i.e., which concurrency problem does this demonstrate? Answer: c) Rewrite the sequence of operations using the standard technique for dealing with concurrency problems of this type for isolation level SERIALIZABLE. In the columns on the right specify the type of requests made. (type your answer into the grid below) You cannot change the time sequence. Time Trans # Requests Transaction 1 Transaction 2 1 2 3 4 5 6. 7 9 10 11 12 13 d) Was the concurrency problem completely solved? If not, what happened and what should be done next? Answer:
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