In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,0,) dissolved in molten cryolite (Na, AlF), resulting in the reduction of the Al,0, to pure aluminum. Suppose a current of 940. A is passed through a Hall-Heroult cell for 71.0 seconds. Calculate the mass of pure aluminum produced.

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In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,0,) dissolved in molten cryolite (Na, AlF), resulting
in the reduction of the Al,0, to pure aluminum.
Suppose a current of 940. A is passed through a Hall-Heroult cell for 71.0 seconds. Calculate the mass of pure aluminum produced.
Be sure your answer has a unit symbol and the correct number of significant digits.
Transcribed Image Text:In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,0,) dissolved in molten cryolite (Na, AlF), resulting in the reduction of the Al,0, to pure aluminum. Suppose a current of 940. A is passed through a Hall-Heroult cell for 71.0 seconds. Calculate the mass of pure aluminum produced. Be sure your answer has a unit symbol and the correct number of significant digits.
Expert Solution
Step 1

we will apply the combined Faraday's law

W = (Q*M )/F*n 

W = weight of mass in grams

Q = quantity of electricity passed

M = molar mass of metal

t = time of electricity passed

F = 1 Faraday = 96500C

n = valency of metal

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