MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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b. Find the
c. Find the probability that a person would wait more than 2 days
![### Statistical Analysis of Medical Treatment Waiting Times
#### Survey Data
The General Social Survey asked 810 people how many days they would wait to seek medical treatment if they were suffering from pain that interfered with their ability to work. The responses are summarized in the following table:
| Number of Days | Frequency |
|----------------|-----------|
| 0 | 19 |
| 1 | 432 |
| 2 | 265 |
| 3 | 67 |
| 4 | 16 |
| 5 | 11 |
| **Total** | **810** |
*You can download the data for further analysis by clicking the "Send data to Excel" button.*
---
#### Probability Distribution
Consider these 810 people to be a population. Let \( X \) be the number of days for a person sampled at random from this population.
**Part 1 of 3**
(a) Construct the probability distribution of \( X \). Round the answers to three decimal places.
The probability distribution can be calculated using the given frequencies and the total number of respondents. For each number of days \( x \):
\[ P(X = x) = \frac{\text{Frequency of } x}{\text{Total Frequency}} \]
To enter values into the table:
| \( x \) | 0 | 1 | 2 | 3 | 4 | 5 |
|---------|-------|-------|-------|-------|-------|-------|
| \( P(x) \) | [ ] | [ ] | [ ] | [ ] | [ ] | [ ] |
---
Please make sure to enter the probability values in the respective boxes and round them to three decimal places. Continue to the next parts by pressing "Submit Assignment."](https://content.bartleby.com/qna-images/question/2ac0b19d-05a9-491c-8461-6accbb8703ad/5f5beadb-a5e2-452d-9a0b-a18259413f49/verneax_processed.jpeg)
Transcribed Image Text:### Statistical Analysis of Medical Treatment Waiting Times
#### Survey Data
The General Social Survey asked 810 people how many days they would wait to seek medical treatment if they were suffering from pain that interfered with their ability to work. The responses are summarized in the following table:
| Number of Days | Frequency |
|----------------|-----------|
| 0 | 19 |
| 1 | 432 |
| 2 | 265 |
| 3 | 67 |
| 4 | 16 |
| 5 | 11 |
| **Total** | **810** |
*You can download the data for further analysis by clicking the "Send data to Excel" button.*
---
#### Probability Distribution
Consider these 810 people to be a population. Let \( X \) be the number of days for a person sampled at random from this population.
**Part 1 of 3**
(a) Construct the probability distribution of \( X \). Round the answers to three decimal places.
The probability distribution can be calculated using the given frequencies and the total number of respondents. For each number of days \( x \):
\[ P(X = x) = \frac{\text{Frequency of } x}{\text{Total Frequency}} \]
To enter values into the table:
| \( x \) | 0 | 1 | 2 | 3 | 4 | 5 |
|---------|-------|-------|-------|-------|-------|-------|
| \( P(x) \) | [ ] | [ ] | [ ] | [ ] | [ ] | [ ] |
---
Please make sure to enter the probability values in the respective boxes and round them to three decimal places. Continue to the next parts by pressing "Submit Assignment."
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