In the general population, height is normally distributed with a mean of 168.7 cm and a standarddeviation of 11.2 cm. You wish to examine whether the basketballers at your local sports andrecreation centre differ in height than the general population. You sampled 28 basketballers andmeasured their height which gave you a mean of 189.8 cm and a standard deviation of 8.5 cm.Calculate the upper limit of the 99% confidence interval. Give your answer to 2 decimal places.

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Answered: In the general population, height is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The average triglyceride level of adult males is 126 milligrams per deciliter. You want to determine whether the true mean male triglyceride level is more than the average. You decide to pull a random sample of eight adult males and measure their triglyceride level. You find the sample mean is 127.9 milligrams per deciliter and the standard deviation is 4.12 milligrams per deciliter. What are the test statistic and the p-value? O The test statistic is 1.9 and the p-value is 0.1174. O The test statistic is 0.1174 and the p-value is 1.9. O The test statistic is 1.46 and the p-value is 1.30. O The test statistic is 0.1174 and the p-value is 1.30. O The test statistic is 1.30 and the p-value is 0.1167.
A recent study of over 1000 parents on cyberbullying showed that a 95% confidence interval of proportion of kids who faced bullying in social media sites and apps is (0.122, 0.194). Find the point estimator of the population proportion of kids who faced bullying in social media sites and apps. Round your answer to three decimal places.
Mason earned a score of 226 on Exam A that had a mean of 250 and a standard deviation of 40. He is about to take Exam B that has a mean of 550 and a standard deviation of 25. How well must Mason score on Exam B in order to do equivalently well as he did on Exam A? Assume that scores on each exam are normally distributed.
The standard deviation of the diameter of a sample of 23 golf balls was 0.19 centimeters. Find the 90% confidence interval of the true standard deviation of the diameter of golf balls. Please include all work showing how you found your answer.
The distribution of weights for newborn babies is approximately normally distributed with a mean of 7.3 pounds and a standard deviation of 0.7 pounds. The middle 95% of newborn babies weigh between , and , pounds. What percent of newborn babies weigh less than 5.9 pounds? Approximately 50% of newborn babies weigh more than , pounds
It takes an average of 12.8 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 51 injured patients to immediately tell the truth about the injury and noticed that they averaged 14.1 minutes for their blood to begin clotting after their injury. Their standard deviation was 4.48 minutes. What can be concluded at the the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? v Select an answer V Hj: ? v Select an answer V c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the populaton mean is significantly different from 12.8 at a =…
A particular fruit's weights are normally distributed, with a mean of 696 grams and a standard deviation of 25 grams. If you pick 26 fruits at random, then 4% of the time, their mean weight will be greater than how many grams? Give your answer to the nearest gram.
It takes an average of 10.2 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will decline if the patient is immediately told the truth about the injury. The EMT randomly selected 60 injured patients to immediately tell the truth about the injury and noticed that they averaged 10.1 minutes for their blood to begin clotting after their injury. Their standard deviation was 1.62 minutes. What can be concluded at the the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and altemative hypotheses would be: Họ: Select an answer H1: ? Select an answer c. The test statistic (please show your answer to 3 decimal places.) d. The p-value = e. The p-value is (? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that .. (Please show your answer to 4 decimal places.) O The data suggest the population mean is not significantly less than 10.2 at a = 0.01, so there is…
Jeremiah earned a score of 530 on Exam A that had a mean of 450 and a standard deviation of 40. He is about to take Exam B that has a mean of 63 and a standard deviation of 20. How well must Jeremiah score on Exam B in order to do equivalently well as he did on Exam A? Assume that scores on each exam are normally distributed.
The average resting heart rate for a normal adult is around 80 beats per minutes. A randomly selected group of 16 people who live in SF was taken and it was found that their average resting heart rate is 71.3 beats per minute. Assume that the standard deviation of the resting heart rate for any normal adult is 18 beats per minute. Test the claim that the average resting heart rate for people who live in SF is less than 80 beats per minute. Round your answer to the nearest tenth of a BPM For credit, the hypothesis test must contain: 1) Claim in terms of the appropriate parameter (e.g. μ = 4.5 m i l e s) 2) Null and alternative hypothesis 3) Sample evidence used 4) Test stat (z or t) , p-value and direction of test. (right, left or two tailed) 5) Whether you rejected or failed to reject the null hypothesis. 6) Conclusion telling us what the test concluded about your original claim.
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a laboratory tested 36 chicken eggs and found that the mean amount of the cholesterol was 230 mg with s = 20 mg. Find a 90% confidence interval for the true mean cholesterol content of an egg.

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