In the following PL/SQL block, determine the values and data types for each of the following cases: DECLARE   v_customer VARCHAR2(50) := 'Womansport2';     v_credit_rating VARCHAR2(50) := 'VERY_GOOD'; BEGIN   DECLARE   v_customer NUMBER(7) := 201;    v_nmae VARCHAR2(25) := 'Unisports';      BEGIN      V_credit_rating := 'GOOD';   END;   END;   The value of v customer in the nested block is:   The value ofv name in the nested block is:   The value of v _credit_rating in the nested block is:   The value of v customer in the main block is:   The value of v name in the main block is:   The value of v_credit_rating in the main block is:

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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  1. In the following PL/SQL block, determine the values and data types for each of the following cases:

DECLARE

  v_customer VARCHAR2(50) := 'Womansport2';  

  v_credit_rating VARCHAR2(50) := 'VERY_GOOD';

BEGIN

  DECLARE

  v_customer NUMBER(7) := 201; 

  v_nmae VARCHAR2(25) := 'Unisports'; 

 

  BEGIN

     V_credit_rating := 'GOOD';

  END;

 

END;

 

  1. The value of v customer in the nested block is:

 

  1. The value ofv name in the nested block is:

 

  1. The value of v _credit_rating in the nested block is:

 

  1. The value of v customer in the main block is:

 

  1. The value of v name in the main block is:

 

  1. The value of v_credit_rating in the main block is:
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