+ @ BScreenshot (2230).png+ NewⒸMy DriveComputersShared with meRecentStarredTrashStorage7.8 GB of 15 GB< Buy storageQ Search in DriveShared with me > póFilescm. It is wrapped with 500 turns of One long wire lies along aplane, passes through theresulting magnetic field atNumber84the resistances are R₁ = R₂ = R₁ = 2.13wwwR₁R₂UnitsOpen withwww(a) Number iIn the figure the current in resistance 6 is i6 = 1.35 A and the resistances are R₁ = R₂ = R3 = 2.13 №, R₁ = 15.7 Q, R5 = 7.21 02, and R₂ =4.72 Q2. What is the emf of the ideal battery?R3R₂When resistors 1 and 2 are conequivalent resistance is 3.670Q +wwR₁R₂→Ro:4Name↓:9+

Given, I6 = 1.35 AR1 = R2 = R3 = 2.13 ΩR4 = 15.7 ΩR5 = 7.21 ΩR6 = 4.72 Ω

In the figure the current in resistance 6 is i6 = 1.35 A and the resistances are R₁ = R₂ = R3 = 2.130, R4 = 15.70, R5 = 7.210, and R6 = 4.72 Q. What is the emf of the ideal battery? Number i R₁ Units R3 www R₂ R₁ R₂ Ro

In the figure the current in resistance 6 is i6 = 1.35 A and the resistances are R₁ = R₂ = R3 = 2.130, R4 = 15.70, R5 = 7.210, and R6 = 4.72 Q. What is the emf of the ideal battery? Number i R₁ Units R3 www R₂ R₁ R₂ Ro

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter24: Magnetic Fields

Section: Chapter Questions

Problem 102A

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+ New
Ⓒ
My Drive
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Recent
Starred
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7.8 GB of 15 GB
< Buy storage
Q Search in Drive
Shared with me > pó
Files
cm. It is wrapped with 500 turns of One long wire lies along a
plane, passes through the
resulting magnetic field at
Number
84
the resistances are R₁ = R₂ = R₁ = 2.13
www
R₁
R₂
Units
Open with
www
(a) Number i
In the figure the current in resistance 6 is i6 = 1.35 A and the resistances are R₁ = R₂ = R3 = 2.13 №, R₁ = 15.7 Q, R5 = 7.21 02, and R₂ =
4.72 Q2. What is the emf of the ideal battery?
R3
R₂
When resistors 1 and 2 are con
equivalent resistance is 3.670
Q +
ww
R₁
R₂
→
Ro
:
4
Name↓
:
9
+

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