In the figure, the center of gravity (CG) of the pole held by the pole vaulter is 1.95 m from the left hand, and the hands are 0.725 m apart. The mass of the pole is 5.0 kg. Calculate the magnitude of the force, in newtons, exerted by his left hand.
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In the figure, the center of gravity (CG) of the pole held by the pole vaulter is 1.95 m from the left hand, and the hands are 0.725 m apart. The mass of the pole is 5.0 kg.
Calculate the magnitude of the force, in newtons, exerted by his left hand.
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- A person carries a plank of wood 2.00 m long with one hand pushing down on it at one end with a force F1 and the other hand holding it up at .500 m from the end of the plank with force F2. If the plank has a mass of 20.0 kg and its center of gravity is at the middle of the plank, what are the magnitudes of the forces F1 and F2?In the figure , the center of gravity (CG) of the pole held by the pole vaulter is 1.85 m from left hand and the hands are 0.675 m apart. The mass of the pole is 5.0 kg. Part (a) calculate the magnitude of the force in newtons exerted by his right hand Part b : calculate the magnitude of the force in newtons exerted by left handA lunch tray is being held in one hand, as the drawing illustrates. The mass of the tray itself is 0.300 kg, and its center of gravity is located at its geometrical center. On the tray is a 1.00 kg plate of food and a 0.330 kg cup of coffee. Obtain the force T exerted by the thumb and the force F exerted by the four fingers. Both forces act perpendicular to the tray, which is being held parallel to the ground.T = N (downward)F = N (upward)
- In the figure, the center of gravity (CG) of the pole held by the pole vaulter is 1.8 m from the left hand, and the hands are 0.69 m apart. The mass of the pole is 5.0 kg. (Image attached) Calculate the magnitude of the force, in newtons, exerted by his right hand. Calculate the magnitude of the force, in newtons, exerted by his left hand.In the figure below, the CG of the pole held by the pole vaulter is 2.04 m from the left hand, and the hands are 0.713 m apart. (Assume the vaulting pole has a mass of 2.52 kg.) Calculate the force (in N) exerted by his right hand. (Enter the magnitude.)A lunch tray is being held in one hand, as the figure illustrates. The mass of the tray itself is 0.172 kg, and its center of gravity is located at its geometrical center. On the tray is a 1.27-kg plate of food and a 0.244-kg cup of coffee. Obtain (a) the force exerted by the thumb and (b) the force exerted by the four fingers. Both forces act perpendicular to the tray, which is being held parallel to the ground.
- The forearm shown below is positioned at an angle with respect to the upper arm, and a 5.6 kg mass is held in the hand. The total mass of the forearm and hand is 2.1 kg, and their center of mass is 16.1 cm from the elbow. (Assume the biceps muscle exerts a force on the forearm that acts vertically.) 5.6 kg B 37.5 cm 4.0 cm (a) What is the magnitude of the force (in N) that the biceps muscle exerts on the forearm for 0-60%7 N (b) What is the magnitude of the force on the elbow joint (in N) for the same angle? N (c) How do these forces depend on the angle 07 The force that the biceps muscle exerts increases and the force on the elbow joint decreases as increases. They both decrease as @ increases. They both increase as increases. They do not depend on 0. The force that the biceps muscle exerts decreases and the force on the elbow joint increases as increases.The (Figure 1) shows two thin beams joined at right angles. The vertical beam is 12.0 kg and 1.00 m long and the horizontal beam is 21.0 kg and 2.00 m long. Neglect the lateral dimensions of the beams.Calculate the gravitational torque on the joined beams about an axis through the corner.In the figure below, the cg of the pole held by the pole vaulter is 2.54 m from the left hand, and the hands are 0.733 m apart. Assume the vaulting pole has a mass of 3.32 kg.) (a) calculate the force (in N) exerted by his right hand ( enter the magnitude.) (b) calculate the force (in N) exerted by his left hand. ( enter the magnitude) (c) If each hand supports half the weight of the pole in the figure below , show that the second condition for equilibrium (net τ = 0) is satisfied for a pivot other than the one located at the center of gravity of the pole. Explicitly show how you follow the steps in the Problem-Solving Strategy for static equilibrium described above. Figure C is the last diagram
- A uniform beam with a length of 2.50 meters and a mass of 85.0 kg rests on two ropes. A person of mass 65.0 kg is standing on the far right end of the beam. The beam is not moving.Calculate the tension in the rope on the left, in Newtons (N).Calculate the tension in the rope on the right, in Newtons (N).A man holds a 171-N ball in his hand, with the forearm horizontal (see the figure). He can support the ball in this position because of the flexor muscle force M , which is applied perpendicular to the forearm. The forearm weighs 24.3 N and has a center of gravity as indicated. Find (a) the magnitude of M and the (b) magnitude and (c) direction (as a positive angle counterclockwise from horizontal) of the force applied by the upper arm bone to the forearm at the elbow joint. Upper arm bone Flexor muscle M Elbow cg joint 0.0510 m+ 0.0890 m 0.330 m (a) Number i Units (b) Number i Units (c) Number i Units >Alunch tray is being held in one hand, as the figure illustrates. The mass of the tray itself is 0.237 kg, and its center of gravity is located at its geometrical center. On the tray is a 1.19-kg plate of food and a 0.241-kg cup of coffee. Obtain (a) the force 7 exerted by the thumb and (b) the force exerted by the four fingers. Both forces act perpendicular to the tray, which is being held parallel to the ground. 0.400 m 0.380 m 0.240 m 0.100 m 0.0600 m henc henc