In the figure, four point charges lie on the corners of a square, with a fifth point charge q located at the center. The two leftmost charges have the same negative charge qn , and the two rightmost charges have the same positive charge q, . Assume that the center charge q is negative. What is the direction of the total electric force on the charge q at the center of the square? What is the direction of the electric field at the center of the square, due to the four corner charges? Answer Bank

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The figure below shows three small, charged beads at the corners of an equilateral triangle. Bead A has a charge of 1.65 µC; B has a charge of 5.40 µC; and C has a charge of -5.10 µC. Each side of the triangle is 0.500 m long. What are the magnitude and direction of the net electric force on A? (Enter the magnitude in N and the direction in degrees below the +x-axis.) y 0.500 m 60.0° C N magnitude o below the +x-axis direction

In the figure, the point charges are located at the corners of an equilateral triangle 29 cm on a side. What is the direction of the force on qa in degrees above the negative x-axis with origin at qa?

The figure below shows three small, charged spheres, all lying along the horizontal axis. Sphere A, at left, has a 6.90 nC charge. Sphere B has a 1.40 nC charge and is 3.00 cm to the right of A. Sphere C has a  −2.80 nC  charge and is 2.00 cm to the right of B. Find the magnitude (in N) and direction of the net electric force on each of the spheres. Three charges lie along a horizontal line. A positive charge labeled qA is on the left. 3.00 cm to its right is a positive charge labeled qB. 2.00 cm to the right of qB is a negative charge labeled qC. Net Force on A magnitude Ndirection    Net Force on B magnitude Ndirection    Net Force on C magnitude Ndirection

Charge Q1 is located at the +70.0-cm mark along an axis. Charge Q2 is located at the -20.0-cm mark along the same axis. Where along the axis must a third charge Q3 be placed in order for the net electric force upon it to be 0 N? We know that: Q₁ = -7.60 μC Q2 = +5.50 μC Express your answer as a coordinate value (+ or -) in cm. Coordinate Location of Q3___ cm

The figure below shows a small, charged sphere, with a charge of q = +42.0 nC, that moves a distance of d = 0.188 m from point A to point B in the presence of a uniform electric field E of magnitude 250 N/C, pointing right. A B + (a) What is the magnitude (in N) and direction of the electric force on the sphere? magnitude N direction ---Select--- (b) What is the work (in J) done on the sphere by the electric force as it moves from A to B? (c) What is the change of the electric potential energy (in J) as the sphere moves from A to B? (The system consists of the sphere and all its surroundings.) PER - PEA = (d) What is the potential difference (in V) between A and B? VB - VA V

a) What is the charge on the other bearing, after separation? b) What was the net charge on both bearings before separation?

A coin that is tossed straight up into the air. After it is released, it moves upward, reaches its highest point and falls back down again. Use one of the following choices (A through G) to indicate the acceleration of the coin during each of the stages of the coin's motion described below. Take up to be the positive direction. Answer choice J if you think that none is correct. A. The acceleration is in the negative direction and constant. B. The acceleration is in the negative direction and increasing. C. The acceleration is in the negative direction and decreasing. D. The acceleration is zero. E. The acceleration is in the positive direction and constant. F. The acceleration is in the positive direction and increasing. G. The acceleration is in the positive direction and decreasing. The coin is mo downward. OE OF OJ O C O A OD OG O B

A positive point charge Q is located at x-a and a negative point charge -Q is at x = -a. A positive charge q can be placed anywhere on the y-axis. Find an expression for (FX, the x -component of the net force on q. Give your answer in terms of Q, q, a, y and constant K. Do your assessment by looking at (F)x when y = 0. net net