In the figure (Figure 1)a 6.00-m-long, uniform beam is hanging from a point 1.00m to the right of its center. The beam weighs 141 N and makes an angle of 30.0⁰ with the vertical. At the right-hand end of the beam a concrete block weighing 100N is hung; an unknown weight w hangs at the other end. Figure w 00 30.0 007 8 100.0 N 1 of 1 > Part A If the system is in equilibrium, what is w? You can ignore the thickness of the beam. 200= Submit ||| ΑΣΦΑ Part B X Incorrect; Try Again; 19 attempts remaining w= Previous Answers Request Answer Submit If the beam makes, instead, an angle of 46.0° with the vertical, what is w? ? Π| ΑΣΦ Annume N ? N

College Physics
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Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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11.60

**Problem 11.60**

In the figure (Figure 1) a 6.00-m-long, uniform beam is hanging from a point 1.00 m to the right of its center. The beam weighs 141 N and makes an angle of 30.0° with the vertical. At the right-hand end of the beam a concrete block weighing 100 N is hung; an unknown weight \( w \) hangs at the other end.

### Figure

#### Diagram Description

The diagram shows a uniform beam with a length of 6.00 meters. The beam is hanging from a pivot point located 1.00 meters to the right of its center. 

- The beam makes an angle of 30.0° with the vertical axis.
- A concrete block, which weighs 100.0 N, is attached to the right-hand end of the beam.
- The pivot point appears to be located 2.00 meters above the right end of the beam.
- An unknown weight \( w \) is hung at the left end of the beam.
- The length of the beam from the pivot point to the right end is shown as 4.00 meters.

### Part A

**Question:**
If the system is in equilibrium, what is \( w \)? You can ignore the thickness of the beam.

**Input Field:**
\[ w \; = \; \_\_\_\_\_\_ \; \text{N} \]

**Submit Button, Previous Answers, Request Answer Button**

**Feedback:**
Incorrect; Try Again; 19 attempts remaining

### Part B

**Question:**
If the beam makes, instead, an angle of 46.0° with the vertical, what is \( w \)?

**Input Field:**
\[ w \; = \; \_\_\_\_\_\_ \; \text{N} \]

**Submit Button, Previous Answers, Request Answer Button**
Transcribed Image Text:**Problem 11.60** In the figure (Figure 1) a 6.00-m-long, uniform beam is hanging from a point 1.00 m to the right of its center. The beam weighs 141 N and makes an angle of 30.0° with the vertical. At the right-hand end of the beam a concrete block weighing 100 N is hung; an unknown weight \( w \) hangs at the other end. ### Figure #### Diagram Description The diagram shows a uniform beam with a length of 6.00 meters. The beam is hanging from a pivot point located 1.00 meters to the right of its center. - The beam makes an angle of 30.0° with the vertical axis. - A concrete block, which weighs 100.0 N, is attached to the right-hand end of the beam. - The pivot point appears to be located 2.00 meters above the right end of the beam. - An unknown weight \( w \) is hung at the left end of the beam. - The length of the beam from the pivot point to the right end is shown as 4.00 meters. ### Part A **Question:** If the system is in equilibrium, what is \( w \)? You can ignore the thickness of the beam. **Input Field:** \[ w \; = \; \_\_\_\_\_\_ \; \text{N} \] **Submit Button, Previous Answers, Request Answer Button** **Feedback:** Incorrect; Try Again; 19 attempts remaining ### Part B **Question:** If the beam makes, instead, an angle of 46.0° with the vertical, what is \( w \)? **Input Field:** \[ w \; = \; \_\_\_\_\_\_ \; \text{N} \] **Submit Button, Previous Answers, Request Answer Button**
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