College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- 26arrow_forwardBlock 1, of mass m1m1m_1 = 1.10 kgkg , moves along a frictionless air track with speed v1v1v_1 = 27.0 m/sm/s . It collides with block 2, of mass m2m2m_2 = 17.0 kgkg , which was initially at rest. The blocks stick together after the collision Part C What is the change ΔK=Kfinal−KinitialΔK=Kfinal−Kinitial in the two-block system's kinetic energy due to the collision? Express your answer numerically in joules.arrow_forwardTwo blocks with masses 4m and 7m are on a collision course with the same initial speeds vj. The block with mass 4m is traveling to the left, and the 7m block is traveling to the right. They undergo a head-on elastic collision and each returns, along the same line as it approached. Find the final speeds of the particles. (Enter your answerss in terms of v, the initial speed of each mass.) Vamf V7mf %3Darrow_forward
- A billiard ball traveling at 5.00 m/s collides with an identical billiard ball initially at rest on the level table. The initially moving billiard ball (A) deflects 60° from its original direction while the other ball, which was initially at rest, travels 30° from the original direction of A. a)Find the speed of each of the masses A and B after the collision? b) Is the collision elastic or inelastic?arrow_forwardOne block of mass m_1=2.0 kg is sliding down along a frictionless ramp from a height of h=2.5 m. It then collides with another block of mass m_2=1 kg and after the collision the stick together. Then, both of the blocks slide together into a region where the coefficient of kinetic friction is 0.500 and comes to a stop after distance d m within that region. a. Find the velocity of the block of mass m1 at the bottom of the ramp. b. Find the velocity of the two-block at which they slide into the region with kinetic friction coefficient 0.500. c. Find the value of distance d at which they stoparrow_forwardQuesitos: The drawing shows a bullet passing through two blocks that rest on a horizontal, frictionless surface. Rule out air resistance. The bullet completely passes through the first block and is buried in the second block. Notice that after the collision, both blocks move. Can the Conservation Principle be applied from Linear Momentum to this three-body system? Justify your answer (Ignore any loss of mass from the first block). Problem: A 4.00-g bullet moves horizontally with velocity of + 355m / s. The mass of the first block is 1150 g, and its velocity after the bullet passes through it it is +0.550 m / s. The mass of the second block is 1530 g. (a) Obtain the speed of the bullet after passing through the first block, (b) obtain the velocity of the second block after the bullet is buried in itarrow_forward
- What types of collisions conserve total momentum of the system? O Inelastic Collisions O Both elastic and inelastic collisions Elastic Collisions No collisions conserve total momentum What types of collisions conserve total kinetic energy of the system? O Inelastic Collisions O Both elastic and inelastic collisions No collisions conserve total kinetic energy Elastic Collisionsarrow_forwardA projectile has undergone an elastic one-dimensional collision with an initially stationary target, along an x axis. The figure below is a graph of position versus time for the projectile and target, before and after the collision. (Two line segments are parallel to the time axis.) Which is true about the masses of the projectile and target? 4 O the projectile's mass is greater O the target's mass is greater O the masses are equalarrow_forwardIn a 100% inelastic one dimensional collision, where one mass (0.50 kg) is initially moving at 1.00 m/s [R] collides with a second mass (1.30 kg) initially at rest, which one of the following statements is true? The total kinetic energy before the collision is the same as the kinetic energy after the collision ) The total kinetic energy before the collision is less than the kinetic energy afte the collision The total initial momentum is greater than the total final momentum The total initial momentum is less than the total final momentum The total kinetic energy before the collision is greater than the total kinetic energy after the collisionarrow_forward
- Block 1 of mass 200 kg slides over a frictionless surface with a velocity of 0.25 cm/s and strikes block 2 of mass 100 kg sliding to the left at 0.75 cm/s. What is the final velocit y of each block if the collision is A) Perfectly elastic? B) Perfectly inelastic? C) If there is an external force of 4000 kg*cm/s^2 to the right for 0.008 s during the perfectly inelasticarrow_forward() THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN BELOW. Block m, of mass 15 kg moving with velocity v = 33 m/s on a frictionless plane collides block mg which is connected to block m3 by a long. massless spring with spring constant k = 7000 N/m: see the figure. Each of blocks mą and mg has a mass of 5 kg. Before the collision, blocks mą and mg are stationary and the spring is relaxed. m2 Frictionless - For parts A. B and Cassume that the collision of blocks m, and ma is completely inelastic. (Because the spring is relaxed before the collision. block mạ does not move at the instant of impact therefore (m, +m2) must move through a finite displacement before any force acts on mg and cause it to move) • For parts D and Eassume that the collision of blocks m, and m, is elastic. (Because the spring is relaxed before the collision. block my does not move at the instant of impact therefore mạ must move through a finite displacement before any force acts on mg and cause it to move)…arrow_forwardProblem: You are lead engineer on the design of a crash test apparatus that verifies collisions of varying types. A m = 2 kg mass, when suspended above from a light-weight wire of L = 1.5 m, is first released at an angle of 90°, and correspondingly a height h = L. The tethered ball swings toward the waiting block of M = 4 kg. collides, then rebounds back to an angle of 0 = 32°. In this case, the collision between m and M is elastic, which prompts M's rightwards motion a distance of Ax = 2.1 m, from which the coefficient of kinetic friction between the block and surface on which it is slid is determined. m L h 0 Marrow_forward
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