In the figure a potential difference of V = 106 V is applied across a capacitor arrangement with capacitances C₁ = 10.7 μF, C₂ = 6.06 μF, and C3 = 4.66 µF. If capacitor 3 undergoes electrical breakdown so that it becomes equivalent to conducting wire, what is the increase in (a) the charge on capacitor 1 and (b) the potential difference across capacitor 1? (a) Number 248.34e-6 (b) Number i 23.21 Units Units C3 с C₂

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My current answers are wrong. Please help, units need to be in C and V. 

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### Capacitor Network Analysis

In this problem, we're analyzing a capacitor network where a potential difference of \( V = 106 \, \text{V} \) is applied across a combination of capacitors. The capacitors have the following capacitances:

- \( C_1 = 10.7 \, \mu\text{F} \)
- \( C_2 = 6.06 \, \mu\text{F} \)
- \( C_3 = 4.66 \, \mu\text{F} \)

The configuration of the capacitors in the circuit is shown in the accompanying diagram.

#### Problem Statement:
If capacitor \( C_3 \) undergoes electrical breakdown, becoming equivalent to a conducting wire, determine the following:
1. **Increase in the charge on capacitor 1** \( \Delta Q_{C_1} \)
2. **Potential difference across capacitor 1** \( V_{C_1} \)

**Diagram:**

The diagram shows:
- A potential difference (V) applied across the network.
- Capacitors \( C_1 \) and \( C_2 \) are connected in parallel with each other.
- Capacitor \( C_3 \) is shown in series with the parallel combination of \( C_1 \) and \( C_2 \).

**Solution:**

The given conditions result in the following calculations:

1. **Charge on Capacitor 1:**
   \[
   \Delta Q_{C_1} = 248.34 \times 10^{-6} \, \text{C}
   \]
   Units: Coulombs (C)

2. **Potential Difference Across Capacitor 1:**
   \[
   V_{C_1} = 23.21 \, \text{V}
   \]
   Units: Volts (V)

By breaking down the circuit and the problem statement, the changes and values can be systematically calculated.

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This transcription approach clearly displays the problem and the solution, facilitating understanding for educational purposes.
Transcribed Image Text:--- ### Capacitor Network Analysis In this problem, we're analyzing a capacitor network where a potential difference of \( V = 106 \, \text{V} \) is applied across a combination of capacitors. The capacitors have the following capacitances: - \( C_1 = 10.7 \, \mu\text{F} \) - \( C_2 = 6.06 \, \mu\text{F} \) - \( C_3 = 4.66 \, \mu\text{F} \) The configuration of the capacitors in the circuit is shown in the accompanying diagram. #### Problem Statement: If capacitor \( C_3 \) undergoes electrical breakdown, becoming equivalent to a conducting wire, determine the following: 1. **Increase in the charge on capacitor 1** \( \Delta Q_{C_1} \) 2. **Potential difference across capacitor 1** \( V_{C_1} \) **Diagram:** The diagram shows: - A potential difference (V) applied across the network. - Capacitors \( C_1 \) and \( C_2 \) are connected in parallel with each other. - Capacitor \( C_3 \) is shown in series with the parallel combination of \( C_1 \) and \( C_2 \). **Solution:** The given conditions result in the following calculations: 1. **Charge on Capacitor 1:** \[ \Delta Q_{C_1} = 248.34 \times 10^{-6} \, \text{C} \] Units: Coulombs (C) 2. **Potential Difference Across Capacitor 1:** \[ V_{C_1} = 23.21 \, \text{V} \] Units: Volts (V) By breaking down the circuit and the problem statement, the changes and values can be systematically calculated. --- This transcription approach clearly displays the problem and the solution, facilitating understanding for educational purposes.
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