In the figure, a 3.8 kg block slides along a track from one level to a higher level after passing through an intermediate valley. The track is frictionless until the block reaches the higher level. There a frictional force stops the block in a distance d. The block's initial speed is vo = 5.8 m/s, the height difference is h = 1.0 m, and Mk = 0.579. Find d. l = 0- Number i Units

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In the figure, a 3.8 kg block slides along a track from one level to a higher level after passing through an intermediate valley. The track is frictionless until the block reaches the higher level. There a frictional force stops the block in a distance d. The block's initial speed is v0 = 5.8 m/s, the height difference is h = 1.0 m, and μk = 0.579. Find d.

 

previous question with diff values are

mass of block is m=4.2kg

5.3m/s initial velocity

Height h=1.2m

kinetic friction coefficient is 0.646

d was 0.35 (incorrect)

also put 4 decimal places?

In the figure, a 3.8 kg block slides along a track from one level to a
higher level after passing through an intermediate valley. The track is
frictionless until the block reaches the higher level. There a frictional
force stops the block in a distance d. The block's initial speed is vo = 5.8
m/s, the height difference is h = 1.0 m, and Mk = 0.579. Find d.
d
u = 0-
Number
i
Units
Transcribed Image Text:In the figure, a 3.8 kg block slides along a track from one level to a higher level after passing through an intermediate valley. The track is frictionless until the block reaches the higher level. There a frictional force stops the block in a distance d. The block's initial speed is vo = 5.8 m/s, the height difference is h = 1.0 m, and Mk = 0.579. Find d. d u = 0- Number i Units
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