In the diagram shown the following is known: Given: AB bisect ZCBD and BD = BC . Prove: AADB = AACB using rigid motion reasoning B (a) Explain why we know that m2CBA= MZDBA but we don't know that M2CAB = MZDAB . Mark the known equal angles. (b) A reflection of AABD across AB leaves what points unmoved ("fixed")? Explain why they don't move. (c) The image of D under the reflection in AB must fall on C. This needs both m2CBA= m2DBA and BD = BC . Explain why. (d) Explain why this reflection in AB now shows that AADB = AACB .

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