-In the clevis shown in Fig. below, find the minimum bolt diameter and the minimum thickness of each yoke that will support a load P= 14 kN without exceeding a shearing stress of 120 MPa and a bearing stress of 200 MPa.
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- simple turnbuckle arrangement is constructed from a 40 mm outside diameter tube threaded internally at each end to take two rods of 25 mm outside diameter with threaded ends. What will be the nominal stresses set up in the tube and the rods, ignoring thread depth, when the turnbuckle carries an axial load of 30 kN? Assuming a sufficient strength of thread, what maximum load can be transmitted by the turnbuckle if the maximum stress 1s limited to 180 MN/m*?The ultimate stress for the hitch ball is 60,000 ksi. (Capacity) The advertisement information is listed in the photos. 1) What is the maximum shear stress? (Demand) (Note you'll need to use half circle for Q) 2) What is the demand capacity stress ratio? V POWER TORQUE. PTWO011 HITCH BALL BOLA DE ENGANCHE 2" BALL DIAMETER 6000 LB. RATING 3-1/4" SHANK LENGTH PTWO011 POWER TORQUE. HITCH BALL BOLA DE ENGANCHE 1" SHANK DIAMETERTwo 35 mm shafts are connected by a flanged coupling. The flanges are fitted with 6 bolts on 125 mm bolt circle. The shafts transmit a torque of 800 N-m at 350 rpm. For the safe stresses mentioned below, Safe shear stress for shaft material = 63 MPa Safe stress for bolt material = 56 MPa Safe stress for cast iron coupling = 10 MPa %3D Safe stress for key material = 46 MPa Calculate: (i) diameter of bolts ; (ii)thickness of flanges ; (iii)key dimensions ; (iv)hub length; and (V)power transmitted.
- Given:a. the force in BD=25KNb. vertical reaction at point C=-10KNc. horizontal reaction at point C=15KNd. resultant of reaction at point C=18.0KNe. allowable tensile (normal) stress in member BD =83.33MPaf. the allowable shear stress in the pin at C =72.7MPaPlease help me solve for:1. What is the required cross-section area and minimum thickness t of member BD?2. What is the required SHEAR cross-section area at point C?3. What is the minimum diameter for the pin at C?(Solve for a value with the combination of mm and N)A flexible cable and rigid boom system is used to lift a load of 65kN at the end of Boom at point C. Points A and B are considered pinned in nature. The allowable shearing stress at all bolts are 250MPa and the allowable bearing stress at all bolts are 300MPa. Note that the initial position of boom is horizontal and segment A and B are vertical. Draw the freebody diagramA 4-T crane is used to lift a 3m x 1.2m x 200mm pre-cst panel. A preader beam is needed to ensure the proper distribution of load in the lifting chains. Consider modulus of elasticity, E=200,000 MPa, allowable shearing stress of lifting pin is 50 MPa, the steel plate used in the spreader beam has an allowable bearing stress of 40 MPa. (All measurement in the figure is in millimeters) 1. Determine the total load in kN, the crane has to carry the the lifting accessories (spreader beam, lifting chains and hooks) has a total mass of 720 kgs. if 2. Determine the average normal stress on each leg of the lifting chain A and B. 3. Determine the required diameter (d) in millimeters of the lifting pin if the allowable shearing stress must not be exceeded (Round to the nearest whole number). 4. Determine the required thickness (t) in millimeters of the steel plate to be used if the allowable bearing stress must not be exceeded. (Round to the neareat whole number)
- SITUATION 2: Find the smallest diameter of bolt and the minimum thickness of each yoke that can be used in the clevis shown in the figure below if P = 400 KN. The shearing strength of the bolt is 300 MPa and the bearing strength is 500 MPa. € YokeA flanged bolt coupling is used to connect a solid shaft 90 mm in diameter to a hollow shaft 100 mm in outsude diameter and 90 mm in inside diameter. If the allowable aring stress in the shafts and the bolts is 60 MPa, how many 10 mm diameter steel bolts must be used on a 200 mm diameter bolt circle so that the coupling will be as strong as the weaker shaft?The figure shows the handle super fast byke and its geometry with forces The cross section at the critical location is elliptical, with a major axis of 3 in and a minor axis of 1.5 in. For a load of 20 kip, estimate the stresses at the inner and outer surfaces of the critical section. 12-in R. 12-in R. 9 in
- Bearing stress 4. Please provide proper discussion and illustration also complete solution and clear solution please thank you Determine the length of a square key to be used for a 3.73 kW, 1800 rpm electric motor if the motor shaft diameter is 35 mm and the width of the key is approximately one-fourth of the shaft diameter. The allowable shearing stress on the key is 2.45 MPa3 in 2. For the C-clamp shown in Fig.1 , a perpendicular force is applied (into the page) at the end of the handle 3.5" from the centerline of the clamp screw. The handle has a diameter D= 1/2" and is made of AISI 1035 CD steel with a yield strength S, = 67 kpsi. The clamp screw is a 5/8 in–18 UNF, with ACME threads. Knowing that the maximum stress in the handle will occur at the location where the handle protrudes from the screw housing, what value of applied screw torque will cause the handle to bend permanently when the clamp is fully closed? What clamp force corresponds to this? Assume that collar friction is negligible and that the coefficient of friction between the threads and the nut is 0.15. Fig. 14) Ball bearings support the rotating axle shown below at points A and D. The rotating axle is loaded by a stationary (non-rotating) force of F = 6.8 kN. In the drawing below, all dimensions are in mm, and all geometry changes (steps in the diameter shaft) have a fillet radius of 3 mm. The axle is machined from AISI cold-drawn steel with an ultimate strength of S_u = 690 MPa and a yield strength of S_y= 580 MPa. Calculate the safety factor at the 6.8 kN load and points B and C, which experience moderate bending moments with a geometric feature that causes a stress concentration. Determine the number of cycles to failure of this part. 30 -10 -250 32 B 6.8 KN 75 -38 100- с 125 10 35 D 30