In the circuit shown in the figure below, C1=26μF, C2=22μF, C3=31μF, and a voltage Vab=48V is applied accross points a and b. After C1 is fully charged, the switch is thrown to the right. What is the final voltage on C1? Express your answer in units of V(Volts) using one decimal place.

In the circuit shown below, V = 23 V, 1 - 3 A, R1 = 9 2 and R2 = 235 2. Calculate the voltage, Vx (in Volts to 1 decimal place) and enter the value in the answer field below. R1 R2 Vx

Complete the table below. Current in R, Resistance R, Current Power in R2 Voltage Resistance R1 Power in R1 in R, SI (W) No (V) (1) P, (W) (2) IRI (A) Ir2 (A) P2(W) 0.051 0.0151 15 0.151 0.046 3 25 0.250 0.076 4 35 0.352 0.107 5 45 0.454 0.138 Average Value of Average Value of R, () R2 (1) 2.

All of the first five questions on this quiz deal with the circuit illustrated in the accompanying diagram. The battery voltage is 80.6 V, and the resistances are R1 = 123 Ohms; R2 = 114 Ohms; R3 = 139 Ohms; R4 = 159 Ohms; R5 = 56 Ohms; and R6 = 199 Ohms. What is the equivalent resistance of this circuit?     608 Ohms     325 Ohms     425 Ohms     170 Ohms rejected

Please provide clear solution. Thank you

The figure below shows a multiloop circuit. The voltages and resistances in the circuit are: V1 = 10.0 V, V2 = 30.0 V, V3 = 58.0 V, R1 = 125.0 Ω, R2 = 155.0 Ω, R3 = 195.0 Ω. Use these values to answer the questions below. (Use the following as necessary: I1, I2, and I3.) (a) Write the equation for the loop ABHEFGA in the order that you go around the loop. −I2 (155.0 Ω) −30.0 V + 10.0 V − I1 (125.0 Ω) = 0 +I2 (155.0 Ω) +30.0 V +10.0 V − I1 (125.0 Ω) = 0 +I3 (155.0 Ω) +58.0 V −10.0 V − I2 (155.0 Ω) = 0 −I3 (195.0 Ω) −58.0 V +10.0 V − I1 (155.0 Ω) = 0 (b) Write the equation for the loop BCKDEHB in the order that you go around the loop. +I2 (155.0 Ω) +30.0 V +10.0 V − I1 (125.0 Ω) = 0 +I3 (195.0 Ω) −58.0 V + 30.0 V + I2 (155.0 Ω) = 0 +I3 (155.0 Ω) +58.0 V −10.0 V − I2 (155.0 Ω) = 0 −I3 (195.0 Ω) −58.0 V +30.0 V − I1 (155.0 Ω) = 0 (C)Write the equation for the loop ABCKDEFGA in the order that you go around the loop. +I3 (155.0 Ω) +30.0 V −58.0 V − I2 (125.0 Ω) = 0 −I3 (195.0 Ω)…

Consider the potential difference between pairs of points in (Figure 1). Suppose that E� = 7.0 V What is the magnitude of the potential difference ΔV14? What is the magnitude of the potential difference ΔV24? What is the magnitude of the potential difference ΔV34?

Based on the % error calculations in procedures A, was there a significant difference between the measured and theoretical values for capacitance? What factors do you think affect the calculation of the % error may it be significant or not?

Find I1, I2, and I3 in figure a, where  E = 11 V. I1 =  A I2 =  A I3 =  A

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