In the calibration step of a thermochemistry experiment, a current of 124 mA, from a 24.0 V source was allowed to flow through the electrical heater for 219 s and was found to result in an increase in the temperature of the calorimeter and its contents of +1.39 K. Given that the energy supplied by an electrical circuit is the voltage multiplied by the current, multiplied by the time, what is the heat capacity of the calorimeter and its contents?

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A: m = 10 kg = 10000 g s = 0.385 J.K−1.g−1 T1 = 100 oC = 373 K T2 = 0 oC = 273 K

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Q: An average man weighs about 70 kg and produces about 10460 kJ of heat per day. Suppose that a man…

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A: The explanation is given below-

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Q: A 0.357 mol sample of N, (g), initially at 298 K and 1.00 atm, is held at constant pressure while…

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