In the American Heart Association journal Hypertension, researchers report that individuals who practiceTranscendental Meditation (TM) lower their blood pressure significantly. If a random sample of 228 male TMpractitioners meditate for 7.9 hours per week with a standard deviation of 2.25 hours, does that suggest that, onaverage, men who use TM meditate more than 7.5 hours per week? Quote a P-value in your conclusion.State the null and alternative hypotheses.Hot = 7.5H₁: > 7.5(Type integers or decimals. Do not round.)Find the test statistic.The test statistic is 2.68.(Round to two decimal places as needed.)Find the P-value.The P-value is 0.007(Round to three decimal places as needed.)xample TextbookClear allFinal check

According to the given information in this question We need to find the test statistic and p value,…

Answered: In the American Heart Association…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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O A myopenmath.com Home - ATI Testing МyOpenMath A shareholders' group is lodging a protest against your company. The shareholders group claimed that the mean tenure for a chief exective office (CEO) was at least 11 years. A survey of 94 companies reported in The Wall Street Journal found a sample mean tenure of 9.5 years for CEOs with a standard deviation of 4 years (The Wall Street Journal, January 2, 2007). You want to formulate and test a hypothesis that can be used to challenge the validity of the claim made by the group, at a significance level of 0.05. Your hypotheses are: H0: μ >11 Ні:д < 11 What is the test statistic for this sample? (Report answer accurate to 3 decimal places.) What is the p-value for this sample? (Report answer accurate to 4 decimal places.) This test statistic leads to a decision to O reject the null O accept the null O fail to reject the null As such, the final conclusion is that there is sufficient evidence to conclude that the population mean tenure for…
A random sample of 160 commercial customers revealed that 32 had paid their accounts within a month of billing. Can normality be assumed for the sample proportion?
A credit score is used by credit agencies (such as mortgage companies and banks) to assess the creditworthiness of individuals. Values range from 300 to 850 with a credit score over 700 considered to be a quality credit risk. According to a survey, the mean credit score is 705.6. A credit analyst wondered whether high-income individuals (incomes in excess of $100,000 per year) had higher credit scores. He obtained a random sample of 34 high-income individuals and found the sample mean credit score to be 724.4 with a standard deviation of 84.4. Conduct the appropriate test to determine if high-income individuals have higher credit scores at the α=0.05 level of significance. 1) Find: P-value 2) Make a conclusion regarding the hypothesis.
Suppose that El Camino is studying the average number of hours students study for classes per week. According to research from 2010 El Camino students spent an average of 21 hours a week studying for classes. El Camino wants to study if this average has changed. To do this they take a random sample of 81 current students and find that the average student spent 19.3 hours studying with a standard deviation of 6.4 hours. (Note: You may assume there are approximately 20,000 El Camino students). (a) Carry out a hypothesis test at α = .05 to test the claim that the average number of hours per week that El Camino students study has changed since 2010. (b) Describe what it would mean in this situation to make a Type I error (c) Describe what it would mean in this situation to make a Type II error (d) Construct a 95% confidence interval for the average number of hours studied by El Camino students per week. Make sure to interpret your interval.
In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with raw garlic Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.1 and a standard deviation of 23.2. Use a 0.01 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? O A. Ho p=0 mg/dL O B. H, p=0mg/dL H, p0 mg/dL OC. Ho H>0 mg/dL O D. H, p=0 mg/dL. H, pz0 mg/dL. H, p<0 mg/dL
On the PSAT test taken by about 1.5 million high school juniors each year, the mean score on the reading portion of the test was 46.9, with a standard deviation of 10.9. The scores are normally distributed. If a student needed a score on this portion of the test that put them in the top 5% of scores nationally to qualify for a particular scholarship, what is the minimum score they must achieve?
Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 42 randomly selected people who train in groups and finds that they run a mean of 47.1 miles per week. Assume that the population standard deviation for group runners is known to be 4.4 miles per week. She also interviews a random sample of 47 people who train on their own and finds that they run a mean of 48.5 miles per week. Assume that the population standard deviation for people who run by themselves is 1.8 miles per week. Test the claim at the 0.01 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
A medical journal published the results of a study to compare the effectiveness of handwashing with soap and handrubbing with alcohol. Health care workers who used handrubbing had a mean bacterial count of 34 per hand with a standard deviation of 65. Health care workers who used handwashing had a mean bacterial count of 67 per hand with a standard deviation of 103. In a random sample of 50 health care workers, all using the same method of cleaning their hands, the mean bacterial count per hand, x, is less than 33. Give your opinion on whether this sample of workers used handrubbing with alcohol or handwashing with soap. Click the icon to view the table of normal curve areas. Since the probability of x being less than 33 is alcohol, and used if this sample of workers used handrubbing with ▼if they used handwashing with soap, it is more likely that this sample of workers
Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of women
The Ankle Brachial Index (ABI) compares the blood pressure of a patient's arm to the blood pressure of the patient's leg. A healthy ABI is 0.9 or greater. In a study, researchers obtained the ABI of 187 women with arterial disease. The results were a mean ABI of 0.86 with a standard deviation of 0.16. At the 1% significance level, do the data provide sufficient evidence to conclude that, on average, women with arterial disease have an unhealthy ABI? Set up the hypotheses for the one-mean t-test. Hou Ha: H
A clinical researcher performs a clinical trial on 20 patients to determine whether a drug treatment has an effect on serum glucose. The sample mean glucose of the patients before and after the treatment are summarized in the following table. The sample standard deviation of the differences was 10. Before TreatmentSample mean glucose (mg/dL): 117 After TreatmentSample mean glucose (mg/dL): 111 What type of hypothesis test should be performed?Unpaired t-testTwo-tailed z-testLeft-tailed z-testPaired t-test What is the test statistic? What is the number of degrees of freedom? Does sufficient evidence exist to support the claim that the voltage of the batteries made by the two manufacturers is different at the α = 0.01 significance level?YesNo
a Leche League International reports that the mean age of weaning a child from breastfeeding is age four to five worldwide. In America, most nursing mothers wean their children much earlier. Suppose a random survey is conducted of 21 U.S. mothers who recently weaned their children. The mean weaning age was 9 months (3/4 year) with a standard deviation of 2 months. Conduct a hypothesis test to determine if the mean weaning age in the U.S. is less than four years old. Conduct a hypothesis test at the 5% level. a. What is the p-value? (Round your answer to four decimal places.) b. What is the test statistic

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