In the 1989 movie "Batman" (likely before your time), the batman was able to execute a turn at high speed using a bat-rope shot out from the batmobile that grabbed a Gotham City lamp post. After executing 90 degrees of turn, the bat-rope was released and left behind for cleanup by the Gotham City Department of Sanitation. Lamp Post M For simplicity, we will assume no friction from the tires on the road (making the centripetal force coming entirely from the bat-rope). Bat-rope is excellent but not infinite and will break if the tension in the rope exceeds Tmax The maximum velocity of the batmobile, Vmax m/s Assuming that the batmobile is only going 76 % of Vmax. what is the rope tension? The time required to make the 90 degree turn, s 1649000 Newtons. Assuming that the batmobile has a mass of m 1213 kg and turns in a circle of radius R = 2.58 meters, calculate all the following: N NOTE: For a 90 degree turn, the distance covered is 1/4 of the circumference of the circle. NOTE: Count the zeroes on the tension carefully. The number should be between 1 and 10 million newtons.

The batman makes a 90 degree turn using rope. The motion for this turn is circular motion. The necessary centripetal force is applied by the tension in rope. 

The centripetal force is given as

$F=\frac{m{v}^2}{r}$

Here $m,v,r$ are mass, velocity, radius of batman.

The rope breaks if maximum tension limit is crossed.