In testing Ho: H = 100 versus H3: µ= 100 versus using a sample size of 325, the value of the teststatistic was found to be 2.16. The p-value (observed level of significance) is best approximated by0.0308O 0.007O 0.4846O 0.96920.0154

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Answered: In testing Ho: H = 100 versus Ha: µ=…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Consider Ho: µ1 = µ2= H3= H4 and sample size are ni= n2= 5, na = 6, n4= 8. a. Complete the ANOVA table. Critical Value / Tabular Value Mean Sum of Source of Variation Sum of Squares df F- value Decision Squares Between - column Within - column 64 240 Total Solutions: b. Using 5% level of significance, would you reject Ho?
With 0.05 significance level, H1: p > 0.5, and the value of test statistics is z = 1.25. Then the P-value is equal to 0.8944 -0.1056 0.1056 None
Below is a table that shows samples of computed p values and the corresponding level of significance, a (alpha). Put the appropriate remarks whether to reject Ho or to accept Ho. Ho is your null hypothesis. Computed p-value Interpretation Level of Significance a 1. p= 0.07 2. p= 0.00 3. p = 0.05 a =0.05 a =0.05 a =0.05
The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers. (Cotinine is used as a biomarker for exposure to nicotine.) The sample size is n=761 and the test statistic is t=55.668. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a significance level of 0.10. State the null and alternative hypotheses. H₁> 2.84 2.84 (Type integers or decimals. Do not round.) The test statistic is (Round to two decimal places as needed.)
1. What is the standardized test statistic? t = ___. 2. What is/are the critical value(s)?
A Z-test for single population mean is conducted with Ha: H < 10, at significance level of 0.05, The most significant result is suggested by the following test statistic -1.65 2.2 4.7 1.96 O3.7 -4.5
For each of the tests, what would be the conclusion if the test were carried out using the α = 0.05 level of significance? H0 : µ = 120, H1:µ ≠ 120, n = 36, S.D of population= 10.3, sample mean = 117.0
The manager of a political party wants to find out the association between the campaign spending (Large, medium and small) and the vote obtained (Majority, Average and minority). Use Chi-squared hypothesis test for association to test that there is an association between the variable in campaign spending and the variable in vote obtained with five percent level of significance. The manager uses MS excel to calculate the Chi-squared stat value and the result is 8.874. Critical value: At 1% = 13.277 :At 5% = 9.488 :At 10% = 7.779 1. State the decision rule 2. Conclusion and decision 3. State the alternative hypothesis and the null hypothesis
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Suppose you want to test the claim that μ > 25.6. Given a sample size of n = 47 and a level of significance of, a=0.01 when should you reject H0?
Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 101.02, y = 100.75, r = 0.852, P-value = 0.000, and y = 5.93 + 0.94x, where x represents the IQ score of the husband. Find the best predicted value of y given that the husband has an lQ of 100? Use a significance level of 0.05. %3D Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is Critical values of the pearson correlation coefficient r (Round to two decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r X = 0.05 a = 0.01 INOTE: To test Ho: p=0 n Jagainst H,: p+0, reject Ho if the absolute value of r is greater than the critical value in the table. 4 0.950 0.990 0.878 0.959 0.811 0.917 7 0.754 0.875 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444…

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In testing Ho: H = 100 versus Ha: µ= 100 versus using a sample size of 325, the value of the test statistic was found to be 2.16. The p-value (observed level of significance) is best approximated by 0.0308 O 0.007 O 0.4846 O 0.9692 O 0.0154