In Problem approximate the real solutions to each quadratic equation to two decimal places.

Given quadratic equation is $23.1-14.1x-0.002x^2=0$.

Given quadratic equation can be written as:

$\begin{array}{rcl}23.1-14.1x-0.002x^2& =& 0\\ -0.002x^2-14.1x+23.1& =& 0\\ 0.002x^2+14.1x-23.1& =& 0\end{array}$

Quadratic formula for quadratic equation,

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Solving using quadratic formula,

$\begin{array}{rcl}x& =& \frac{-\left(14.1\right)\pm \sqrt{{\left(14.1\right)}^2-4\left(0.002\right)\left(-23.1\right)}}{2\left(0.002\right)}\\ & =& \frac{-14.1\pm \sqrt{198.81+0.1848}}{0.004}\\ & =& \frac{-14.1\pm \sqrt{198.99}}{0.004}\\ & =& \frac{-14.1\pm 14.10}{0.004}\\ & =& \frac{-14.1+14.1}{0.004}or \frac{-14.1-14.1}{0.004}\\ & =& 0 or 7050\end{array}$