In part B For solving P abs. How did it get the value of 13600?Also, show where the value is in the steam table Given DataPra blo.44mm Hh vaiX= 0.9947m:7200 kglho+(1)Tei=12°cTro = 21°cTo find mcwStep2Pabs: Pahm- PcPabs: (101-325)- (13600x 610-14x 10% 9. p1) kea1000Pabs. (9.81 PyProm 8team hables at P=19:88KPheg:2358 4 Kalkyh2=hf+xhfg, (251 5)+ (0.9947x23s94)h2:2597.40 kJ lkgStep3c)h3-hf: 2515 k5 lryQlost : 8gained

Given data Pc= 610.44 mm of Hg vacuum. And hf= 251.5 kJ/kg hfg=2358.4 kJ/kg ,

Answered: In part B For solving P abs. How did it…

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In part B For solving P abs. How did it get the value of 13600? Also, show where the value is in the steam table

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

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Entropy

In physics, entropy means the amount of disorder or the degree of randomness associated with a thermodynamic system. The system is not self-organized when the entropy of the system is high. For instance, when a system is at an elevated temperature, its molecules are in random motion, vibrating and colliding with each other. During this scenario, the probability of finding a molecule at a particular place twice, is low. Under this circumstance, the system can be said to be in a high entropy.

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In part B For solving P abs. How did it get the value of 13600? Also, show where the value is in the steam table

Given Data
Pra blo.44mm Hh vai
X= 0.9947
m:7200 kglho+(1)
Tei=12°c
Tro = 21°c
To find mcw
Step2
Pabs: Pahm- Pc
Pabs: (101-325)- (13600x 610-14x 10% 9. p1) kea
1000
Pabs. (9.81 Py
Prom 8team hables at P=19:88KP
heg:2358 4 Kalky
h2=hf+xhfg, (251 5)+ (0.9947x23s94)
h2:2597.40 kJ lkg
Step3
c)
h3-hf: 2515 k5 lry
Qlost : 8gained

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