College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A 5μF capacitor with air between the metal plates is connected to a 12V battery. The battery is then
removed, leaving the capacitor charged.


(a) Calculate the charge on the capacitor.

(b) The air between the plates is replaced by oil with er = 3. Find the new value of capacitances and the new potential difference between the plates.

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Follow-up Question

But I found this equation for non-vacuum between the plate, I no need to deduct the Er of air 1.005?

Please see attachment.

C
& & A
d
Values of
ET
for certain materials.
Material
Air
Glass
Nylon
Wood
Relative permittivity, &
1.005
6.7
3.7
2.1
expand button
Transcribed Image Text:C & & A d Values of ET for certain materials. Material Air Glass Nylon Wood Relative permittivity, & 1.005 6.7 3.7 2.1
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Follow-up Question

In part (b), do I need to take over the relative permittivity of AIR, that mean

C new = 3*5μF/1.0006  ?

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Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question

But I found this equation for non-vacuum between the plate, I no need to deduct the Er of air 1.005?

Please see attachment.

C
& & A
d
Values of
ET
for certain materials.
Material
Air
Glass
Nylon
Wood
Relative permittivity, &
1.005
6.7
3.7
2.1
expand button
Transcribed Image Text:C & & A d Values of ET for certain materials. Material Air Glass Nylon Wood Relative permittivity, & 1.005 6.7 3.7 2.1
Solution
Bartleby Expert
by Bartleby Expert
SEE SOLUTION
Follow-up Question

In part (b), do I need to take over the relative permittivity of AIR, that mean

C new = 3*5μF/1.0006  ?

Solution
Bartleby Expert
by Bartleby Expert
SEE SOLUTION
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