In open-heart surgery a small amount of energy will defibrillate the heart. (a) What voltage is applied to the 9.57 µF capacitor of a heart defibrillator that stores 46.7 J of energy? |kV (b) Find the amount of stored charge. mc
Q: (a) What is the energy stored in the 10.0 µF capacitor of a heart defibrillator charged to 9.00×103…
A: Given: The potential difference of capacitor is V=9×103 V. The capacitance of capacitor is C=10 µF.
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Q: n open-heart surgery a small amount of energy will defibrillate the heart. (a) What voltage is…
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Q: (a) What voltage (in kV) must be applied to the 10.0 µF capacitor of a heart defibrillator to store…
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Q: In open-heart surgery a small amount of energy will defibrillate the heart. (a) What voltage is…
A: capacitance = C = 9.74 μF= 9.74 X 10-6 F energy = U = 43.8 J voltage = V = ?
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Q: In open-heart surgery a small amount of energy will defibrillate the heart. (a) What voltage is…
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Q: In open heart surgery a much smaller amount of energy will defibrillate the heart. (a) What voltage…
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A: Data We have Capacitance, C=18.0 µF=18×10-6F Voltage,v= 6.40 ✕ 103 V
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Q: In open heart surgery a much smaller amount of energy will defibrillate the heart.(a) What voltage…
A: (a) The energy stored in the capacitor is, U=12CV2⇒V=2UCV=260.0 J8.00×10-6 FV=3.87×103 VV=3.87 kV
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