In HERTZ (rounded to 3 sig figs), approximately how frequently does this 1) device cycle through the full range of total charge magnitudes (from its maximum, through o to its minimum, and all the way back through o to its initial/maximum)? DON'T FORGET TO PROVIDE SOME KIND OF DIAGRAM! In seconds, find how much TIME will elapse from t=0 until precisely the 2) second instant the current is running at a maximum value but in the negative direction (the second time, as measured from t=0, that the current reaches 1= -15 Amperes). You may round to something like 3 sig. figs. 3) a) In Amperes per second, find the instantaneous rate at which the current changes with respect to time at the very first instant the current value is 1=0 Amperes. You may round to something like 3 sig figs. b) At this moment (described above), explain whether the current is growing increasingly negative, increasingly positive, decreasingly positive or decreasingly negative. Thoroughly and convincingly explain how you know. HINT for both the above. Whenever we talk about an 'instantaneous rate, we are talking about a derivative, no? Yes. 4) Assume that the whole phenomenon/experiment is re- done with all the same given equations and values EXCEPT: This time lo = -45 Amperes (instead of +15 Amperes). Provide answers to ALL the above three questions under these new conditions. You can re-calculate and/or provide verbal explanations, but you must fully explain how each of your above three answers does or does not change. 6) TRUE or FALSE and SHOW WHY!: 1 = +45 cos [377t + (pi)] is "A SOLUTION" to the Dif. Equation AND the new condition lo = -45 A

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The volume current density in medium 1(x ≥ 0, €,₁ = 1, and σ₁ = 20 µS/m) is J₁ = 100ax + 20ay - 50az A/m². Obtain the volume cur- rent density in medium 2(x ≤ 0, €,2 = 5, 0280 µS/m). Also compute 01, 02, and p, at the interface. What are the E and D fields on both sides of the interface?

Just #4

(1) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 10 m and cross-sectional area A = 4.5 mm2 lies along the x-axis between e = 0 and z = L. The material obeys Ohm's law, and its resistivity varies along the rod ~(1 -). where po = 5 x 10 4N · m. The end of the rod at z = 0 is at a potential L² according to p = Po Vo = 30 V greater than the end at z = L. B) What is the current, in units of miliamperes in the rod? Answer: