In Exercises 9 and 10, use the TI-84 Plus display to make a decision to reject or fail to reject the null hypothesis at the level of significance. Make your decision using the standardized test statistic and using the P-value. Assume the sample sizes are equal. 9. α- 0.05 10. α-0.01 2-SampZTest 2-SampZTest z=2.956485408 P=. 0031118068 X1=2500 X2=2425 kn1=120 z=1.941656065 P=. 0260893059 X1=44 X2=42 In1=50

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use the TI-84 Plus display to make a decision to reject or fail to reject the null hypothesis at the level of significance. Make your decision using the standardized test statistic and using the P-value. Assume the sample sizes are equal.

### Hypothesis Testing with TI-84 Plus Display

**Instructions:**
In Exercises 9 and 10, use the TI-84 Plus display to make a decision to reject or fail to reject the null hypothesis at the specified level of significance. Make your decision using the standardized test statistic and the P-value. Assume the sample sizes are equal.

---

**Exercise 9:**
- **Significance Level (\(\alpha\)):** 0.05

**2-SampZTest Display:**

- Hypothesis: \(μ_1 > μ_2\)
- Test Statistic (z): 2.956485408
- P-value: 0.0013118068
- Sample Mean 1 (\(\bar{x}_1\)): 1.25
- Sample Mean 2 (\(\bar{x}_2\)): 2.425
- Sample Size 1 (\(n_1\)): 120

**Decision:**
- Since the P-value (0.0013) is less than \(\alpha\) (0.05), reject the null hypothesis.

---

**Exercise 10:**
- **Significance Level (\(\alpha\)):** 0.01

**2-SampZTest Display:**

- Hypothesis: \(μ_1 > μ_2\)
- Test Statistic (z): 1.94165065
- P-value: 0.0260833059
- Sample Mean 1 (\(\bar{x}_1\)): 44
- Sample Mean 2 (\(\bar{x}_2\)): 42
- Sample Size 1 (\(n_1\)): 50

**Decision:**
- Since the P-value (0.0261) is greater than \(\alpha\) (0.01), fail to reject the null hypothesis.

---

**Conclusion:**

- In **Exercise 9**, with a significance level of 0.05, the analysis shows a significant difference, leading to rejection of the null hypothesis.
- In **Exercise 10**, at a stricter significance level of 0.01, the evidence is not strong enough to reject the null hypothesis.
Transcribed Image Text:### Hypothesis Testing with TI-84 Plus Display **Instructions:** In Exercises 9 and 10, use the TI-84 Plus display to make a decision to reject or fail to reject the null hypothesis at the specified level of significance. Make your decision using the standardized test statistic and the P-value. Assume the sample sizes are equal. --- **Exercise 9:** - **Significance Level (\(\alpha\)):** 0.05 **2-SampZTest Display:** - Hypothesis: \(μ_1 > μ_2\) - Test Statistic (z): 2.956485408 - P-value: 0.0013118068 - Sample Mean 1 (\(\bar{x}_1\)): 1.25 - Sample Mean 2 (\(\bar{x}_2\)): 2.425 - Sample Size 1 (\(n_1\)): 120 **Decision:** - Since the P-value (0.0013) is less than \(\alpha\) (0.05), reject the null hypothesis. --- **Exercise 10:** - **Significance Level (\(\alpha\)):** 0.01 **2-SampZTest Display:** - Hypothesis: \(μ_1 > μ_2\) - Test Statistic (z): 1.94165065 - P-value: 0.0260833059 - Sample Mean 1 (\(\bar{x}_1\)): 44 - Sample Mean 2 (\(\bar{x}_2\)): 42 - Sample Size 1 (\(n_1\)): 50 **Decision:** - Since the P-value (0.0261) is greater than \(\alpha\) (0.01), fail to reject the null hypothesis. --- **Conclusion:** - In **Exercise 9**, with a significance level of 0.05, the analysis shows a significant difference, leading to rejection of the null hypothesis. - In **Exercise 10**, at a stricter significance level of 0.01, the evidence is not strong enough to reject the null hypothesis.
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