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In Exercises 53-58, evaluate each piecewise function at the given values of the independent variable. 3x + 5 if x <0 14x + 7 if x2 0 53. f(x) = a. f-2) b. f(0) с. (3) (6x – 1 if x <0 7x + 3 if x 2 0 54. f(x) : a. f-3) b. f(0) с. f(4) Sx + 3 l-(x + 3) if x< -3 if x2 -3 55. g(x) a. g(0) b. g(-6) c. g(-3) Sx + 5 l-(x + 5) if x< -5 if x2 -5 56. g(x) = a. g(0) b. g(-6) c. g(-5) 9 if x* 3 57. h(x) = X - 3 if x = 3 а. h(5) b. h(0) c. h(3) x - 25 if x + 5 58. h(x) : X - 5 10 if x = 5 a. h(7) b. h(0) с. h(5) 6.

In Exercises 53-58, evaluate each piecewise function at the given values of the independent variable. 3x + 5 if x <0 14x + 7 if x2 0 53. f(x) = a. f-2) b. f(0) с. (3) (6x – 1 if x <0 7x + 3 if x 2 0 54. f(x) : a. f-3) b. f(0) с. f(4) Sx + 3 l-(x + 3) if x< -3 if x2 -3 55. g(x) a. g(0) b. g(-6) c. g(-3) Sx + 5 l-(x + 5) if x< -5 if x2 -5 56. g(x) = a. g(0) b. g(-6) c. g(-5) 9 if x* 3 57. h(x) = X - 3 if x = 3 а. h(5) b. h(0) c. h(3) x - 25 if x + 5 58. h(x) : X - 5 10 if x = 5 a. h(7) b. h(0) с. h(5) 6.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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In Exercises 53-58, evaluate each piecewise function at the given values of the independent variable. 3x + 5 if x <0 14x + 7 if x2 0 53. f(x) = a. f-2) b. f(0) с. (3) (6x – 1 if x <0 7x + 3 if x 2 0 54. f(x) : a. f-3) b. f(0) с. f(4) Sx + 3 l-(x + 3) if x< -3 if x2 -3 55. g(x) a. g(0) b. g(-6) c. g(-3) Sx + 5 l-(x + 5) if x< -5 if x2 -5 56. g(x) = a. g(0) b. g(-6) c. g(-5) 9 if x* 3 57. h(x) = X - 3 if x = 3 а. h(5) b. h(0) c. h(3) x - 25 if x + 5 58. h(x) : X - 5 10 if x = 5 a. h(7) b. h(0) с. h(5) 6.
Transcribed Image Text:In Exercises 53-58, evaluate each piecewise function at the given values of the independent variable. 3x + 5 if x <0 14x + 7 if x2 0 53. f(x) = a. f-2) b. f(0) с. (3) (6x – 1 if x <0 7x + 3 if x 2 0 54. f(x) : a. f-3) b. f(0) с. f(4) Sx + 3 l-(x + 3) if x< -3 if x2 -3 55. g(x) a. g(0) b. g(-6) c. g(-3) Sx + 5 l-(x + 5) if x< -5 if x2 -5 56. g(x) = a. g(0) b. g(-6) c. g(-5) 9 if x* 3 57. h(x) = X - 3 if x = 3 а. h(5) b. h(0) c. h(3) x - 25 if x + 5 58. h(x) : X - 5 10 if x = 5 a. h(7) b. h(0) с. h(5) 6.
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