In Exercises 33–38, express the function, f, in simplified form. Assume that x can be any real number. 33. f(x) = V36(x + 2)² 34. f(x) = V81(x – 2)2 35. f(x) = V32(x + 2)³ 36. f(x) = V48(x – 2)³ 37. f(x) = V3x² – 6x + 3 38. f(x) = V5x2 – 10x + 5 %3D

Q: 75,81

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Q: Number 32

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Q: +1 Differentiate the function f (x) = In +1

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Q: EXERCISE 6 (PSAT – 20151028 Section 4, Q9) (Calculator permitted) f (x) = x2 + 4(x – 3) Which of the…

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Q: In Exercises 19–22, show there is a number c, with 0 ≤ c ≤ 1, such that f(c) = 0.  19. F(x) = x3…

A: Use intermediate value theorem

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A: Given: -

Q: Exercises 19–22, show there is a number c, with 0 ≤ c ≤ 1, such that f(c) = 0.  19. F(x) = x3 +x2- 1

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Q: Find the absolute maximum and minimum values on the interval: g(x) = In(x² + 6x + 20), [-5, 1]

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Q: In exercises 20-21, verify that( fo g)(x) = x and (go f)(x) = x %3D X+6 20. f(х) - Зx- 6, g(x) = 3…

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Q: 3 Show that the function f(x) = Vx – 5 is one to one function. %3D

A: The objectives to show that the function f(x) is one to one function.

Q: 5. Show that the function f (x) has roots between (0,2) x + 2x – 3 f(x) = %3D x – 1

A: Given that: f(x)=x2+2x-3x-1

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A: Since f(u) is not clear. Considering two cases to solve the problem:

Q: Prove that the function f(x) = x3 – 6x2 + 15x - 18 is strictly increasing on R. %3D

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Q: In Exercises 3–10, differentiate the expression with respect to x, assuming that y is implicitly a…

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A: Invertible function:

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A: mean value theorem

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A: Given that, fx=3x2+4x+2      ...(1)

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Q: The domain of function x) = In(2– x) is %3D

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Q: Compute f(c+h)−f(c) at the indicated point. f(x)=6x2​; c=4

A: Given : Function : f(x) = 6x2   To find : f(c+h)−f(c) at c = 4.

Q: in Exercises 21-26, a function h(x) is defined in terms of a differen- 21. Mx) (x) 23. h(x) = -(-x)…

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Q: 3 Show that the function f(x) = Vx – 5 is one to one function.

A: The given function is: fx=x-53