In Exercises 11-16, find all values of x satisfying the given conditions. yı = 13x – 4, y2 = 5x + 10, and yı exceeds y2 by 2. yı = 10x + 6, y2 = 12x – 7, and yı exceeds y, by 3. yı = 10(2x – 1), y2 = 2x + 1, and yı is 14 more than 8 times y2- yı = 9(3x - 5), y2 = 3x – 1, and yı is 51 less than 12 times y2- yı = 2x + 6, y2 = x + 8, y3 =x, and the difference between 3 times yı and 5 times y2 is 22 less than y3. yi = 2.5, y2 = 2r + 1, y3 = x, and the difference between 2 times y and 3 times y2 is 8 less than 4 times y3.

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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In Exercises 11-16, find all values of x satisfying the given
conditions.
yı = 13x – 4, y2 = 5x + 10, and yı exceeds y2 by 2.
yı = 10x + 6, y2 = 12x – 7, and yı exceeds y, by 3.
yı = 10(2x – 1), y2 = 2x + 1, and yı is 14 more than
8 times y2-
yı = 9(3x - 5), y2 = 3x – 1, and yı is 51 less than
12 times y2-
yı = 2x + 6, y2 = x + 8, y3 =x, and the difference between
3 times yı and 5 times y2 is 22 less than y3.
yi = 2.5, y2 = 2r + 1, y3 = x, and the difference between
2 times y and 3 times y2 is 8 less than 4 times y3.
Transcribed Image Text:In Exercises 11-16, find all values of x satisfying the given conditions. yı = 13x – 4, y2 = 5x + 10, and yı exceeds y2 by 2. yı = 10x + 6, y2 = 12x – 7, and yı exceeds y, by 3. yı = 10(2x – 1), y2 = 2x + 1, and yı is 14 more than 8 times y2- yı = 9(3x - 5), y2 = 3x – 1, and yı is 51 less than 12 times y2- yı = 2x + 6, y2 = x + 8, y3 =x, and the difference between 3 times yı and 5 times y2 is 22 less than y3. yi = 2.5, y2 = 2r + 1, y3 = x, and the difference between 2 times y and 3 times y2 is 8 less than 4 times y3.
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