= In each of the following situations you apply a force FA 140 N. Rank the following according to the amount of work done by FÅ going from largest to smallest. (Drawing a diagram might be helpful.) You apply FA horizontally along flat, horizontal ground on a mass of 10 kg for 2 m with no friction. You apply FA at an angle of 30° above the horizontal along flat, horizontal ground on a mass of 10 kg for 2 m with no friction. You apply 2 × FA at an angle of 30° above the horizontal along flat, horizontal ground on a mass of 10 kg for 2 m with no friction. You apply FA horizontally along flat, horizontal ground on a mass of 10 kg for 2 m with a kinetic friction coefficient of 0.4. You apply FA horizontally along flat, horizontal ground on a mass of 20 kg for 2 m with a kinetic friction coefficient of 0.4. You apply FA on a mass of 10 kg straight up to lift the mass 2 m.

Part A Compute the kinetic energy, in joules, of an automobile of mass 1650 kg traveling at a speed of 56.0 km/h. Submit Correct Part B Previous Answers By what factor does the kinetic energy change if the speed is doubled? Submit | ΑΣΦ Request Answer BMW ?

The power required for an object sliding on a rough, level surface to overcome friction is P = -bv, where v is the speed of the object. What are the SI units of b? kg/s O kg /s? O kg/m O kg /m? O kg · m/s? none of these

4. Here we prove a version of the work-kinetic energy theorem for an object moving in 1-D subject to a constant force. Consider a mass m, traveling initially at speed v, on which a constant net force F is applied in the same direction as its motion over a distance d. After the net force has acted over this distance, the speed of the object is v2. In terms of m, F, v1, v2, and d only, V, A) What is the acceleration of the mass? t=0 m F d t>0_m B) What is the time over which the mass travels the V, distance d? [Use one equation of constant acceleration to find this.] C) Use another equation of constant acceleration to relate m, F, v,, v2, and d. Show that the product W = Fd is equal to the change in the mass’s kinetic energy.

1) You run forward, pulling a sled behind you with a force of 250 N. If you expend 2,500 Joules, how many meters did you run? Answer w/

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Calculate the work done by friction as a 3.7 kg box is slid along a floor from point A to point B in the figure along paths 1, 2, and 3. Assume that the coefficient of kinetic friction between the box and the floor is 0.19. (Figure 1) Enter your answers numerically separated by commas. Express your answers using two significant figures.   W1,W2,W3= ______ J

The displacement vector from the grocery store door to your car is ∆x = (5 i – 8 j ) m but because of the strong gust, you have to apply a force F in a slightly different direction to keep your cart moving straight from the door to the car, F = (30 i + 4π j ) N. How much work do you do? a) 306.8 J                               b) 49.5 J                                           c) 250.5 J