Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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In Drosophila, the gene eyeless (ey) is on the fourth chromosome, and four wings (fw) and
legs for antennae (lfa) are both on the third chromosome 20 cM apart. Consider that mutations
in all three genes each cause recessive
various phenotypes amongst the offspring of the test cross shown below (note that the comma
separates alleles on the same chromosome, and the semicolon separates different
chromosomes):
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- In the fruit fly, dumpy wings (d) and purple eyes (p) are encoded by mutant alleles that are recessive to those that produce wild type traits; long wings (d+) and red eyes (p+). These two genes are on the same chromosome. In a particular lab, two researchers Walt and Jesse crossed a fly homozygous for dumpy wings and purple eyes with a fly homozygous for the wild type traits. The F1 progeny, which had long wings and red eyes, was then crossed with flies that had dumpy wings and purple eyes. Unfortunately, the progeny of this cross somehow escaped. To prevent their other projects from contamination, they decided to spend an exceptionally boring hour in the lab catching and counting the progeny and found the following: long wings, red eyes – 482 dumpy wings, purple eyes – 473 long wings, purple eyes – 23 dumpy wings, red eyes - 22 What is the genetic distance between these two loci? a. 4.5 cM b. 55 cM c. 45 cM d. 49.5 cM e. 4.7 cMarrow_forwardConsider the following three autosomal recessive mutations in Drosophila:vestigial wings (v); wild type is long (v+)black body color (b); wildtype is gray (b+)plum eyes (p); wildtype is red (p+)A vestigal, gray, red female (homozygous for all three genes) is crossed with a long wing, black, plum male (homozygous for all three genes). The F1 female progeny are mated with triple homozygous recessive males. Here is the phenotypic data for the F2 progeny:vestigal; gray; red 580long wings; black; plum 592vestigal; black; red 45long; gray; plum 40vestigal; black; plum 89long; gray; red 94vestigal; gray; plum 3long; black; red 5A total of 1448 progeny were counted.Which one of the following values is the approximate distance between the plum eye color and black body color loci?arrow_forwardIn jabuticaba tree plant, Plinia cauliflora, the AA, Aa plants round fruit and aa oval fruit, the CC, Cc individuals show dark purple fruit and cc individuals are yellow; for the B locus B1B1 plants have all the fruit in their bark, B2B2 plants have fruit in the branches only and B1B2 plants have fruit in their bark and branches. A trihybrid jabuticaba having the genotype AaB1B2Cc is self-fertilized. Is there complete dominance at the B loci, yes or no? Please explain.arrow_forward
- Vermilion eye color in Drosophila is sex-linked and recessive. What would be the phenotypes of maleand female progenies of a cross between a 6 vermilion female and 6 wild-type (red) male. what is the f1 and f2 generation. if a reciprocal cross is done containing 6 WT females with 6 mutant males what is the F1 and F2 generation. Do they contain the single gene or double gene?arrow_forwardBecause of non-disjunction in some stocks of Drosophila. melanogaster, about 1 in 65,000 egg cells have two copies of the X chromosome and about 1 in 375 egg cells have no X chromosome. Assuming that meiosis in males is ‘always normal', what is the expected frequency of XXX females and XO males arising from any number of fertilized eggs? Do not be concerned as to whether it is lethal or not.arrow_forwardTwo genes, m (apical meristem) and r (starburst rhizosomes), are linked on chromosome #5 in pea plants. Both genes are recessive to wild type and found to be 8 MU apart. If a wild type heterozygote is test- crossed, and produces 91 apical meristem plants and 8 apical, starburst plants from a total of 200 plants were produced, how many wild type plants will be produced? 4 8. 12 16arrow_forward
- Give typed explanation In pea plants, the tall allele (T) is dominant to the dwarf allele (t) and the yellow pea color allele (Y) is dominant to the green pea color allele (y). Cross TtYy with Ttyy. What would be the genotype and phenotype ratios in their offspring? (Please include the gametes produced by each parent.)arrow_forwardIn Drosophila, the genes st (scarlet eyes), ss (spineless bris- tles), and e (ebony body) are located on chromosome 3, with map positions as indicated: st SS e 44 58 70 Each of these mutations is recessive to its wild-type allele (st*, dark red eyes; ss*, smooth bristles; e*, gray body). Phenotypically wild-type females with the genotype st ss e*/st* st* ss+ e were crossed with triply recessive males. Predict the phenotypes of the progeny and the frequen- cies with which they will occur assuming (a) no interfer- ence and (b) complete interference.arrow_forwardThe data set attached summarizes F2 numbers from an F1 cross arising from two, true-breeding Drosophila strains (P generation), which differ with respect to two mutant traits. Here are the hypothesis: Leg length - The wild-type and mutant alleles for leg length are incomplete dominant relative to each other. Justification: The data set includes three phenotypic categories for leg length: wild type (long leg), medium leg, and truncated wings. The presence of three distinct phenotypes suggests an incomplete dominance pattern, where the heterozygous individuals exhibit an intermediate leg length phenotype (medium leg). The absence of purebred short-legged individuals supports the idea that the long leg allele is dominant over the short leg allele. This shows that mode of inheritance is incomplete dominance of the alleles relative to each other. Since the data does not mention any specific differences between males and females, we can assume that the mode of inheritance for the trait is…arrow_forward
- A cross was performed using Drosophila melanogaster involving a female known to be heterozygous for both ebony body and sepia eyes and a male known to be homozygous wild type male. The resulting progeny were allowed to mate with one another to produce the data set. Three repetitions of the experiment were conducted. The following data were produced from the crosses. Test these data to determine if they are significantly different from the expected phenotypic ratio. Use the 5% level of significance. Your answer should include the hypothesized cross in genotypes, the Chi-squared value, the critical value and whether you reject or do not reject for each experiment. Wild eye Wild body – 112, Wild eye Ebony body – 40, Sepia eye Wild body – 35, Sepia eye Ebony body – 11arrow_forwardIn DrosophilaI, yellow body (y), crossveinless (cv), and forked bristles (f) are all found in the X chromosome, in that order. Yellow is 14 map units from crossveinless, and crossveinlessis 32 map units from forked. A yellow, forked female is crossed to a crossveinless male. An F1 female is crossed to a yelow, crossveinless, forked male, yielding the F2 generation. In the F2, what is the probability of obtaining progeny that express crossveinless and forked, but not yellow? Assume a coefficient of coincidence of 1. In the F2, what is the probability of obtaining progeny that are completely wild type? In the F2, what is the probability of obtaining progeny that express crossveinless, but not yellow or forked?arrow_forward
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