In analyzing the equilibrium of a flat, rigid object, one should first choose an axis about which torques can be calculate. Which of the following is true regarding the choice of axis? a) The axis must pass through the object's center of mass. b) The axis must pass through one end of the object. c) The axis must be either the x axis or the y axis. d) The axis must pass through a point within the object. e) Any axis within or outside the object can be chosen.

) The distance between the centers of the wheels of a motorcycle is 155 cm. The center of mass of the motorcycle, including the rider, is 88.0 cm above the ground and halfway between the wheels. Assume the mass of each wheel is small compared with the body of the motorcycle. The engine drives the rear wheel only. What horizontal acceleration of the motorcycle will make the front wheel rise off the ground? (There are a number of views on how to do this online, if you have difficulty with this problem look them up. One view is to calculate the torque about the point of contact on the ground and also the around the center of mass and set them equal to each other.) (a = 8.631 m/s)

D Question 1 For an object in equilibrium the net torque acting on it vanishes only if each torque is calculated about: O the center of mass O the geometrical center O the point of application of the force O the center of gravity the same point

When opening a door, you push on it perpendicularly with a force of 52.5 N at a distance of 0.825m from the hinges. a) What torque are you exerting relative to the hinges?

Give one example in which the net force acting on an object is zero yet the net torque is non zero .b. give another example in which the net torque acting on an object is zero and the net force is non zero

What is the direction of the torque for each of the following situations?   right is in the positive x-direction left is in the negative x-direction up is in the positive y-direction down is in the negative y-direction     r vector is up, F vector is down.   r vector is down, F vector is to the right   r vector is to the right, F vector is also to the right.   r vector is to the right, F vector is down.   r vector is to the right, F vector is up.   r vector is up, F vector is to the left   1. Positive (out of the page, counterclockwise) 2. Negative (into the page, clockwise) 3. Zero

The center of mass of the arm shown in the figure is at point A. Find the magnitudes (in N) of the tension force F and the force F which hold the arm in equilibrium. (Let 8 = 24.0°.) Assume the weight of the arm is 48.3 N. IF 8.00 cm 29.0 cm 1₂ 354 X Draw a diagram showing the forces and distances. Find the sum of the torques about point O, and set this equal to zero. Solve your equation for F₁. N 340.30 X Apply Newton's second law in the x and y directions, and solve for F Sx Pythagorean theorem to calculate F. . N and F You will need your value of F. Then use the sy'