In an effort to estimate the mean amount spent per customer for dinner at a major Atlanta restaurant, data were collected from 64 randomly selected customers. The sample mean was calculated as $27.75 with a sample standard deviation of $4. We wish to develop a 91% confidence interval for the mean amount spent per customer for dinner at this restaurant. Assume that the standard deviation of the amounts spent by ALL customers is $4.30.
In an effort to estimate the
Fill in the missing pieces of the 91% confidence interval.
x¯±zCFσn√x¯±zCFσn
Note: we assume the standard deviation of the amounts spent by ALL customers is $4.30.
Since we know the standard deviation of the population, this allows us to use the standard
x¯x¯ is
z is
CF is
σσ is 4.3
n is
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