in accelerates opposite to the motion from 12.0 to 7.50 m/s in 2.30 s to join another dolphin in play. What average force was exerted to slow the first dolphin if it was moving horizontally? (The gravit

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A 35.0-kg dolphin accelerates opposite to the motion from 12.0 to 7.50 m/s in 2.30 s to join another dolphin in play. What average force was exerted to slow the first dolphin if it was moving horizontally? (The gravitational force is balanced by the buoyant force of the water.)

 

Expert Solution
Step 1

We know that the first equation of the motion is given as 

v=u+at

where v is the final velocity, u is the initial velocity 

a is the acceleration t is time  to achieve a velocity v

We also know that the newton second law of motion is given as 

F= ma 

where F is the force 

m is the  mass. 

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