In a survey the planning value for the population proportion is P* = 0.45. How large a sample should be selected to provide a 90% confidence interval with a margin of error of 0.06? Select one: a. 186 b. 268 c. 168 d. 286

Use the given data to find the minimum sample size required to estimate a population proportion or percentage. Margin of error: 0.06; confidence level 90%; p and q unknown ..... (Round up to the nearest integer.) n=

When the population standard deviation is unknown and the sample size is greater than 30, what table value should be used in computing a confidence interval for a mean?      a. z b. t c. chi square d. standard deviation

If X=68​, σ=14​, and n=66​, construct a 95​% confidence interval estimate of the population​ mean, μ

Consider a sample data with x=25 and s=2. Compute a chebyshev’s interval for which at least 89% of the data will lie?

Tina catches a 14-pound bass.  She does not know the population mean or standard deviation.  So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds.  Find the t and calculate a 95% (α = .05) confidence interval.

Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the confidence level. Round the margin of error to four decimal places

With 99% confidence, maximum error is 0.06 and the proportion p = 0.5. Find the sample size. a. 463 b. 436 c. 364 d. 643 e. NONE OF THE ABOVE A

If n=200 and X=70, construct a 99% confidence interval estimate for the population proportion. SAS (Round to four decimal places as needed.)

Suppose a one sided test for a proportion resulted in a p-value of 0.06. What would the p-value be if the test were two tail test? Select one: A. It would still be 0.06. B. It would be 0.3. C. It would be 0.12. D. There is no way to calculate this without completely redoing the original test with a new alternative hypothesis.