In a series RC circuit shown, the switch is closed and after a short time, the charge q on the capacitor is 5.2 x 10-5 C. What is the current in the resistor at this time?

RC Circuits: In this circuit, the battery has voltage E = 2.0 V, and each resistor has resistance R = 10 Q. The capacitor, which has capacitance C = 1.0 x10-12 F, carries. initial charge 3.0 x 10-12 C, with the positive charge on the right plate. The switch is closed at time t = 0 s. a. Immediately after time t = 0, what current flows through resistor 1? b. A long time later, what current flows through resistor 1? c. Sketch a rough graph of the charge on the right capacitor plate, as a function of time. દ 8. ww C R 2 R3

The values of the components in a simple series RC circuit containing a switch and an initially uncharged capacitor (see figure below) are C = 1.50 µF, R = 2.30 MN, and E = 10.0 V. R (a) the charge on the capacitor... ...a long time after the switch is closed 900 = ..4.1 s after the switch is closed q = (b) the current in the resistor... ...immediately after the switch is closed In = HA ..4.1 s after the switch is closed I = HA ... a long time after the switch is closed I, = (c) The rate at which energy, 4.1 s after the switch is closed, is... ...being dissipated in the resistor Presistor = ...being stored in the capacitor Рсаpаcitor %3D µW

Consider the circuit shown below where the battery has an emf of = 16.3 V, the resistors have the resistances of R₁-8.4 Q2, R₂ = R3 = 3.8 02, and the capacitance of the capacitor is C=3 μF. The switch S is closed at t=0. The capacitor is initially uncharged. If you wait long enough after the switch is closed, at t=%, what would be the charge on the capacitor? Please express your answer using two decimal places in units of μC .he capacitor is initially uncharged. E Answer: R₁ M R₂ R3 C