ConstantsImagine the Carnot heat engine represented by the p vs.V diagram given in (Figure 1).Because there is no heat flow during an adiabatic process, there is no entropy change for either the gas or thesurroundings. (This is an approximation, but we can wrap the gas sample in lots of insulation to isolate it from thesurroundings.)During the isothermal compression, an amount of heat energy Qc flows out of the gas at a temperature Tc. Thisresults in a decrease in the gas's entropy of magnitude S = Qc/Tc. However, heat energy will naturally flow out ofthe gas into the surroundings only if there is a (slight) temperature difference between the gas and the surroundings.gasPart EIn a real isothermal compression, the temperature of the surroundings must bethe temperature of thegas.FigureComplete the sentence above.1 of 1>greater thanless thanSubmitRequest AnswerIsothermalAdiabaticPart F Complete previous part(s)AdiabaticPart G Complete previous part(s)Isothermal→V( Return to AssianmentProvide Eeedback

Answered: In a real isothermal compression, the…

In a real isothermal compression, the temperature of the surroundings must be , the temperature of the gas. Complete the sentence above. greater than O less than

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Properties of Pure Substances

A substance with fixed chemical composition throughout is called a pure substance like water, air, and nitrogen. A pure substance does not have to be a single element or compound. A mixture of two or more phases of a pure substance is also a pure substance as long as the chemical composition is the same for all phases. These substances mainly have a constant/ uniform composition. The substances also have fixed boiling and melting points. A pure substance takes part in a chemical reaction to form predictable products.

Question

Constants
Imagine the Carnot heat engine represented by the p vs.
V diagram given in (Figure 1).
Because there is no heat flow during an adiabatic process, there is no entropy change for either the gas or the
surroundings. (This is an approximation, but we can wrap the gas sample in lots of insulation to isolate it from the
surroundings.)
During the isothermal compression, an amount of heat energy Qc flows out of the gas at a temperature Tc. This
results in a decrease in the gas's entropy of magnitude S = Qc/Tc. However, heat energy will naturally flow out of
the gas into the surroundings only if there is a (slight) temperature difference between the gas and the surroundings.
gas
Part E
In a real isothermal compression, the temperature of the surroundings must be
the temperature of the
gas.
Figure
Complete the sentence above.
1 of 1
>
greater than
less than
Submit
Request Answer
Isothermal
Adiabatic
Part F Complete previous part(s)
Adiabatic
Part G Complete previous part(s)
Isothermal
→V
( Return to Assianment
Provide Eeedback

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