In a random sample of 70 patients undergoing a standard surgical procedure, 16 required medication for postoperative pain. In a random sample of 85 patients undergoing a new procedure, only 17 required medication. Construct a 98% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures. Interpret the results. A physician claims that the proportion of patients who need pain medication is the same for both procedures. Does the confidence interval contradict the claim?

Q: Several years ago, 44% of parents who had children in grades K-12 were satisfied with the quality of…

A: The claim is that 44% of parents who had children in grades K-12 were satisfied with the quality of…

Q: As part of the Pew Internet and American Life Project,, researchers conducted two surveys in late…

A: Given: n1= 800 ,x1= 584 n2= 2253 ,x2= 1059 At 95.0 % confidence level , z score= 1.96 Need to find…

Q: In a random sample of 100 customers, the items that customers purchased were tracked. It was found…

A: Given,sample size(n)=100sample proportion(p^)=0.171-p^=1-0.17=0.83α=1-0.90=0.1α2=0.05Z0.05=1.645

Q: Several years ago, 36% of parents who had children in grades K-12 were satisfied with the quality of…

A:

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: A random sample of 230 people living in Seattle found that 83 of them had a pet. A random sample of…

A: Solution: Given information: n1= 230 Sample size of people iving in Seattle n2= 172  Sample size of…

Q: Several years ago, 39% of parents who had children in grades K-12 were satisfied with the quality of…

A: From the provided information, 39% of parents who had children in grades K-12 were satisfied with…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Sample taken for ages 19 to 25 2253 men and 2629 women random sample In which 986 men and 923 women…

Q: Dr. Jean discovered a new treatment for skin disease. She believes that the new treatment is more…

A: Given Data: p^1=0.7333    n2=30p^2=0.75    n2=100   pooled value of proportion:…

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…

A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120   significance level =…

Q: In a survey of 1037 US adults ages 65 and over, 643 were concerned about getting the flu. A 99%…

A: Given,n=1037x=643p^=xnp^=6431037=0.6201-p^=1-0.620=0.380α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: A telephone poll of 1,000 adult Americans was reported in an issue of a news magazine. One of the…

A: A telephone poll of 1,000 adult Americans was reported in an issue of a news magazine. One of the…

Q: In a clinical trial, 50 patients who received a new medication are randomly selected. It was found…

A: Solution: Let X be the number of patients suffered serious side effects from this new medication and…

Q: sample of 624 applicants to the Durmstrang Institute of Sorcery, 133 were accepted. Construct a 90%…

A: Given that  X=133 , n=624 , p=20%=0.20

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: What formulas are used to find the confidence interval? Researchers comparing the effectiveness of…

A: According to the given information in this questionWe need to construct 95% confidence interval

Q: A recent poll indicated that 42% of men supported raises taxes to fund additional park services.…

A:

Q: Several years ago, 43% of parents who had children in grades K-12 were satisfied with the quality of…

A: Given  Several years ago, 43% of parents who had children in grades K-12 were satisfied with the…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: A sample of 200 females and 500 males found that 78.3% of females and 35.1% males supported…

A: given data female :  p^1 = 0.783     n1 = 200male :  p^2 = 0.351     n2 = 50095% ci for p1-p2.

Q: A researcher is interested in testing the claim that the proportion of children (ages 8-12) who like…

A: given data sample 1  :children    n1  = 53sample 2 : teenager    n2   = 112ci for difference in…

Q: Several years ago, 44% of parents who had children in grades K-12 were satisfied with the quality of…

A: We have given that 44% of parents who had children in grades K-12 were satisfied with the quality of…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: Recent research commissioned by Vodafone suggests that older workers are the happiest employees (BBC…

A: Solution: Given information: n= 120 Sample size of worker  x = 68  worker feel fulfilled at work.…

Q: Several years ago, 46% of parents who had children in grades K-12 were satisfied with the quality of…

A: Given information Population proportion p = 0.46 We have given that; a recent poll asked 1,045…

Q: A recent poll indicated that 42% of men supported raises taxes to fund additional park services.…

A: given data men: p^1 = 0.42     n1 = 21women : p^2 = 0.64    n2 = 1999% ci for p1-p2.

Q: A recent poll indicated that 42% of men supported raises taxes to fund additional park services.…

A: Given The data is as follows: Sample proportion of men, p^1=0.42 Sample proportion of women,…

Q: A recent poll indicated that 42% of men supported raises taxes to fund additional park services.…

A: The question is about confidence interval Given : Sample prop. of men supported raises taxes to fund…

Q: Several years  ago, 41 % of parents who had children in grades  K-12 were satisfied with the quality…

A: Given,n=1175x=477p^=xnp^=4771175=0.4061-p^=1-0.406=0.594α=1-0.90=0.1α2=0.05Z0.05=1.645

Q: In a random sample of 100 drivers, 80 were using seat belts while driving. Construct a 95%…

A:

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: Several years​ ago, 42​% of parents who had children in grades​ K-12 were satisfied with the quality…

A: Let p be the population proportion of parents satisfied with the quality of education the students…

Q: A research poll of 1501 adults showed that 1051 of respondents believe in global warming. Find a 98%…

A:

Q: Several years ago, 39% of parents who had children in grades K-12 were satisfied with the quality of…

A:

Q: Several years ago, 43% of parents who had children in grades K-12 were satisfied with the quality of…

A:

Q: Several years ago, 46% of parents who had children in grades K-12 were satisfied with the quality of…

A: Given  p=0.46, n=1055, X=488

Q: Several years ago, 48% of parents who had children in grades K-12 were satisfied with the quality of…

A: Given : n = 1035 X = 497

Q: According to a recent Government survey, 6% of all merchandise sold in the U.S. gets returned.  A…

A: It is given that sample size (n) is 80 and x is 12.

Q: 8. In clinical trials of the allergy medicine Clarinex (5 mg) it was reported that 50 out of 1655…

A: Here , We needed to construct the 95%95\%  confidence interval for the difference between population…

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…

Q: s. Rains believes more seniors from PLD plan to a niors at Lafayette. In a random sample of 35 PLD…

A: The formula for computing sample proportions is,  The confidence interval for the difference in…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.