In a random sample of 470 homeowners selected from a large suburban area, 30% indicated that they have serious problems with exessive noise from their neighbors. Estimate with 90% confidence the proportion of all homeowners in that suburban area who have this problem. (Give the confidence interval in percentages.)

Q: Out of a sample of 600 adults aged 18 to 30, 162 still lived with their parents. Based on this,…

A:

Q: A Dean of a certain business school is interested in the difference in proportions of A's given by…

A: Givenn1=800x1=240n2=800x2=160p1^=x1n1=240800=0.3p2^=x2n2=160800=0.2α=1-0.95=0.05α2=0.025zα2=1.96

Q: A survey of 120 female freshmen showed that 9 did not wish to work after marriage.  Find the 99%…

A:

Q: A sociologist wants to construct a 94% confidence interval for the proportion of teenagers who uses…

A: Given, p=0.23 E=0.02 z value at 94% confidence is Zc=1.88 n=?

Q: A scientist wondered if there was a difference in the average daily intake of dairy products between…

A: Reviewing information, X : Daily intake of dairy products of MenY : Daily intake of dairy products…

Q: A sample of 100 homes in city A and 100 homes in City B was taken to estimate the proportion of the…

A: Given that, A sample of 100 homes in city A and 100 homes in city B were taken to estimate the…

Q: A sample of 200 found that 43.2% of those sampled consumed more than 2 alcoholic  beverages  a week.…

A: Given:

Q: An accounting firm has 1,220 clients. From a random sample of 122 clients, 110 indicated very high…

A: From the given information, the sample size is 122 clients. Among 122 clients, 110 indicated very…

Q: The Centers for Disease Control and Prevention reported a survey of randomly selected Americans age…

A: Confidence interval for Proportions : The following is the formula for confidence interval of the…

Q: A sample of 13 concerts showed their average noise levels were 82 decibels and their standard…

A: Solution: Let X be the noise level From the given information, x-bar=82 decibels, s=7 decibels and…

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: According to a report on consumer fraud and identity theft, Indiana had 1671 complaints of identity…

A:

Q: An accounting firm has 1,190 clients. From a random sample of 119 clients, 108 indicated very high…

A: Given:

Q: A report statesb that 33% of home owners had a vegetable garden. how large a sample is needed to…

A: p=33%=0.33, E=5%=0.05

Q: 67% out of 150 pupils from school A passed an exam; 62% of 120 pupils at school B passed. Estimate…

A: Given : n1 = 150 n2 = 120 confidence level,c=0.9

Q: people from Tanjung Malim has been given cholesterol tests, and 60 of these people had levels over…

A: We have given that,  Favorable cases (X) = 60 and sample size (n) = 150 Then,  We will find the 95%…

Q: A report statesb that 44% of home owners had a vegetable garden. how large a sample is needed to…

A: Answer: Using the given data, A report stated that 44% of home owners had a vegetable garden, P =…

Q: A survey of 100 customers showed that 36 of them preferred brand B of a particular product. Give a…

A: p = proportion of people vote for BSample size : n = 100Number of favorable outcomes : x =…

Q: In a random sample of 500 Americans, 25% indicated that they have a cat for a pet. Estimate with 97%…

A:

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A: Obtain the 95% confidence interval for the true proportion of adult residents who are parents in…

Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…

A: Given information

Q: business conducts a random sample of 89 of its customers and find that 44 of them think the company…

A:

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: You want to get a 95% confidence interval for the difference between the percentage of females with…

A:

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 100…

A: According to the given information, we have Out of 100 adult residents sampled, 88 had kids. 99%…

Q: According to a report on consumer fraud and identity theft, California had 1439 complaints of…

A: Let x denote the number of complaints of identity theft in California. x=1439 The total number of…

Q: Out of 54 randomly selected patients of a local hospital who were surveyed, 42 reported that they…

A: Given that, The total patients n are 54 and the total patients who were satisfied x are 42.

Q: A survey found that 39 of 66 people who don't drink coffee often have trouble sleeping and 44 of 88…

A: Solution: Let X1 be the number of noncoffee drinkers who have trouble sleeping, n1 be the sample…

Q: A scientist claims that 65% of U.S. adults believe humans contribute to an increase in global…

A: Given  A scientist claims that 65% of U.S. adults believe humans contribute to an increase in global…

Q: A researcher wanted to compare the percentages of men and women who play the lottery.  They randomly…

A:

Q: According to a report on consumer fraud and identity theft, Montana had 1447 complaints of identity…

A: Given that, x=1447,n=3643 The sample proportion is,

Q: Suppose a marketing company computed a 96% confidence interval for the true proportion of customers…

A: The objective of the question is to understand the meaning of the given 96% confidence interval for…

Q: A recent poll indicated that 42% of men supported raises taxes to fund additional park services.…

A: The question is about confidence interval Given : Sample prop. of men supported raises taxes to fund…

Q: In a random sample of 600 adults, 270 described themselves as vegetarians. Construct a 99%…

A: In a random sample of 600 adults, 270 described themselves as vegetarians.

Q: Sleep apnea is a disorder in which you have one or more pauses in breathing or shallow breaths while…

A: Obtain the 99% confidence interval for the proportion of individuals who suffer from sleep apnea who…

Q: A student found that in a random sample of 300 people in a town, 105 play sports. Based on this…

A: Given that, X = 105 N = 300 90% confidence level

Q: A recent study by the McGraw-Hill company showed that 61% (1621) of college students use their…

A: Given, Proportion of college students use their smartphones for study = 0.61Total number of students…

Q: A research poll of 1501 adults showed that 1051 of respondents believe in global warming. Find a 98%…

A:

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 400…

A: Solution: Let X be the number of parents had kids and n be the sample number of adults. From the…

Q: An actuary is interested in estimating the proportion of young adults who plan to have children…

A: We need to construct the 99% confidence interval for the population proportion. We have been…

Q: The American Heart Association is about to conduct in anti smoking campaign and wants to know the…

A: Solution: Out of a sample of 1421 Americans over 35, 412 smoke.  Sample size: n = 1421 The number of…

Q: A survey of 80 recent arcanum students showed that 46 were ready for summer break. Find the 95%…

A: Obtain the 95% confidence interval for the true proportion of students ready for summer break. The…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.