In a random sample of 26 people, the mean commute time to work was 34.6 minutes and the standard deviation was 7.2 minutes. Assume the population is normally distributed and use a t-distribution to construct a 80% confidence interval for the population mean u. What is the margin of error of u? Interpret the results. The confidence interval for the population mean u is (Round to one decimal place as needed.)

In a random sample of 26 people, the mean commute time to work was 34.6 minutes and the standard deviation was 7.2 minutes. Assume the population is normally distributed and use a t-distribution to construct a 80% confidence interval for the population mean u. What is the margin of error of u? Interpret the results. The confidence interval for the population mean u is (Round to one decimal place as needed.)

Name: In a random sample of 26 people, the mean commute time to work was 34
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: In a random sample of 26 people, the mean commute time to work was 34.6 minutes and the standard deviation was 7.2 minutes. Assume the population is normally distributed and use a t-distribution to construct a80% confidence interval for the populati

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The distribution of study times for first-year students follow a Normal distribution with a standard deviation σ = 48 minutes. Suppose a sample of 344 students found that the mean study time for these students was x¯= 170 minutes per week. Use this to find a 94.38% confidence interval to estimate the mean study time for all students. We are 94.38% confident that the mean study time for first-year students is between the following ( answer) minutes and ( answer) minutes. The answer needs to be the mean study time for first-year students is between what amount of minutes and the following minutes.
The standard deviation, S, for the annual medical cost of 24 households was found to equal $1689 find a 95% confidence interval for the standard deviation of the annual medical cost for all households. Assume medical costs are normally distributed.
In a recent sample of 89 used cars sales costs, the sample mean was $6,225 with a standard deviation of $3,151. Assume the underlying distribution is approximately normal. Which distribution should you use for this problem? Construct a 95% confidence interval for the population mean cost of a used car.
In a random sample of four mobile devices, the mean repair cost was $65.00 and the standard deviation was $13.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 99% confidence interval for the population mean. Interpret the results. The 99% confidence interval for the population mean u is ( ). (Round to two decimal places as needed.)
In a random sample of seven cell phones, the mean full retail price was $414.50 and the standard deviation was $171.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 99% confidence interval for the population mean μ. Interpret the results.
In a random sample of 5 mobile devices, the mean repair cost was $60.00 and the standard deviation was $12.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Interpret the results.
Suppose a sample of 30 students are given an IQ test. The sample has a standard deviation of 12.23 points. Assuming IQ test score follow a normal distribution, suppose the researcher wishes to obtain a 90% confidence interval for the population standard deviation.
From a sample of 37 graduate students, the mean number of months of work experience prior to entering an MBA program was 36.63. The national standard deviation is known to be 19 months. What is a 90% confidence interval for the population mean? A 90% confidence interval for the population mean is 10 (Use ascending order. Round to two decimal places as needed.) ...
In a random sample of 17 people, the mean commute time to work was 30.2 minutes and the standard deviation was 7.1 minutes. Assume the population is normally distributed and use a t- distribution to construct a 95% confidence interval for the population mean y. What is the margin of error of y? Interpret the results.
Calculate the point estimate. An independent researcher wishes to estimate the average amount of money a young professional spends in buying coffee in Starbucks each month. A sample of 164 young professionals who are regular customers of Starbucks found the mean to be P3200. Assuming that the standard deviation of the population is P215. Find the 86% confidence interval of the population mean.
Assume that a sample is used to estimate a population mean. Find the 90% confidence interval for a smaple of size 46 with a mean of 68.5 and a standard deviation of 6.6. Enter the answer as an open-interval (parentheses) accurate to one decimal place (because the sample statistics are reported accurate to one decimal place).
In a random sample of ten cell phones, the mean full retail price was $433.00 and the standard deviation was $208.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 99% confidence interval for the population mean μ. Interpret the results.