MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- The distribution of study times for first-year students follow a Normal distribution with a standard deviation σ = 48 minutes. Suppose a sample of 344 students found that the mean study time for these students was x¯= 170 minutes per week. Use this to find a 94.38% confidence interval to estimate the mean study time for all students. We are 94.38% confident that the mean study time for first-year students is between the following ( answer) minutes and ( answer) minutes. The answer needs to be the mean study time for first-year students is between what amount of minutes and the following minutes.arrow_forwardThe standard deviation, S, for the annual medical cost of 24 households was found to equal $1689 find a 95% confidence interval for the standard deviation of the annual medical cost for all households. Assume medical costs are normally distributed.arrow_forwardIn a recent sample of 89 used cars sales costs, the sample mean was $6,225 with a standard deviation of $3,151. Assume the underlying distribution is approximately normal. Which distribution should you use for this problem? Construct a 95% confidence interval for the population mean cost of a used car.arrow_forward
- In a random sample of four mobile devices, the mean repair cost was $65.00 and the standard deviation was $13.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 99% confidence interval for the population mean. Interpret the results. The 99% confidence interval for the population mean u is ( ). (Round to two decimal places as needed.)arrow_forwardIn a random sample of seven cell phones, the mean full retail price was $414.50 and the standard deviation was $171.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 99% confidence interval for the population mean μ. Interpret the results.arrow_forwardIn a random sample of 5 mobile devices, the mean repair cost was $60.00 and the standard deviation was $12.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Interpret the results.arrow_forward
- Suppose a sample of 30 students are given an IQ test. The sample has a standard deviation of 12.23 points. Assuming IQ test score follow a normal distribution, suppose the researcher wishes to obtain a 90% confidence interval for the population standard deviation.arrow_forwardFrom a sample of 37 graduate students, the mean number of months of work experience prior to entering an MBA program was 36.63. The national standard deviation is known to be 19 months. What is a 90% confidence interval for the population mean? A 90% confidence interval for the population mean is 10 (Use ascending order. Round to two decimal places as needed.) ...arrow_forwardIn a random sample of 17 people, the mean commute time to work was 30.2 minutes and the standard deviation was 7.1 minutes. Assume the population is normally distributed and use a t- distribution to construct a 95% confidence interval for the population mean y. What is the margin of error of y? Interpret the results.arrow_forward
- Assume that a sample is used to estimate a population mean. Find the 90% confidence interval for a smaple of size 46 with a mean of 68.5 and a standard deviation of 6.6. Enter the answer as an open-interval (parentheses) accurate to one decimal place (because the sample statistics are reported accurate to one decimal place).arrow_forwardIn a random sample of ten cell phones, the mean full retail price was $433.00 and the standard deviation was $208.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 99% confidence interval for the population mean μ. Interpret the results.arrow_forward
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