In a population with two alleles, that are in HW equilibrium, the frequency of the recessive allele is 0.3. What is the proportion of the population that is homozygous for the dominant allele? .54 .049 .49 .09

According to Hardy-Weinberg equilibrium the allele frequencies and genotype frequencies will be same generation after generation.

Suppose, the frequency of dominant allele (A) is= p and the frequency of recessive allele (a) is= q.

According to H-W equilibrium p+q=1

The allelel frequency of recessive allele is 0.3. So, q= 0.3 (given).

Hence, the frequency of dominant allele (A) is p = (1-q) = (1-0.3)=0.7

So, p=0.7 and q=0.3