In a Millikan experiment, two horizontal parallel plates are 3.5 cm apart. A sphere A whose mass is equal to 4.2 x 10^-17 kg remains in suspension, while the potential difference between the plates is 5.00 V and the upper plate is positive. a. Determine the charge on the sphere. b. What is the magnitude of the sphere's excess or deficiency of electrons?

a) Calculate the acceleration in meters per second squared of the electron if the field strength is 2.50 ✕ 104 N/C.

Q1

What is the magnitude of the repulsive force between a 3.4 mC charge and a 6.3 mC charge if they are separated by a distance of 93 centimeters? Report your answer kN  rounded up to the tenths place

An electron with kinetic energy ? is traveling along the positive ?-axis, which is along the axis of a cathode‑ray tube, as shown in the figure. There is an electric field ?=14.0×104 N/C pointed in the positive ?-direction between the deflection plates, which are 0.0600 m long and are separated by 0.0200 m.   Determine the minimum kinetic energy ?min the electron can have and still avoid colliding with one of the plates.

2e ++ 2003 Thomson Brooks Cole v=0 + Figure P16.19 + 79e + |—d — + + + + (c16p19) In Rutherford's famous scattering experiments (which led to the planetary model of the atom), alpha particles (having charges of +2e and masses of 6.64×10-27 kg) were fired toward a gold nucleus with charge +79e. An alpha particle, initially very far from the gold nucleus, is fired at 4.60×107 m/s directly toward the gold nucleus as in Figure P16.19. How close does the alpha particle get to the gold nucleus before turning around? Assume the gold nucleus remains stationary.

What is the total electrostatic potential energy of a hydrogen atom (which consists of an electron orbiting a proton at a distance of 5.3 Å)?  Note that this will be a negative number given the formula you're using... Note: for this question, there may be more than one correct answer!       -4.34 x 10-18 J     -13.7 eV     -27.1 eV     -8.19 x 10-8 J

A simple and common technique for accelerating electrons is shown in the figure, which depicts a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to pass through.Randomized VariablesE = 2.7 × 104 N/C   Calculate the horizontal component of the electron's acceleration if the field strength is 2.7 × 104 N/C. Express your answer in meters per second squared, and assume the electric field is pointing in the negative x-direction as shown in the figure.