In a liquid culture, the number of bacteria grows at a proportional rate depending on the number of cells present. At the start, there are 5000 cells present in the culture. After 2 hours, there are 25 000 bacteria. If this unlimited growth is constant each time, what is the doubling time of the bacteria? 0.861 hr O b. 0.917 hr O c. 1.045 hr O d. 0.582 hr (y-3)/(x+1) dy = y dx is a separable differential equation. Select one: O True O False

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Chapter6: Exponential And Logarithmic Functions
Section6.1: Exponential Functions
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It's only for Calculus , again Calculus not other subjects. Hi dude, I need help, Please Show complete answer and correct answers the 2 questions only, Tysm!
In a liquid culture, the number of bacteria grows at a proportional rate depending on the number of cells
present. At the start, there are 5000 cells present in the culture. After 2 hours, there are 25 000 bacteria. If
this unlimited growth is constant each time, what is the doubling time of the bacteria?
Oa.
0.861 hr
O b. 0.917 hr
O c. 1.045 hr
O d. 0.582 hr
(y-3)/(x³+1) dy = y"dx is a separable differential equation.
Select one:
O True
O False
Transcribed Image Text:In a liquid culture, the number of bacteria grows at a proportional rate depending on the number of cells present. At the start, there are 5000 cells present in the culture. After 2 hours, there are 25 000 bacteria. If this unlimited growth is constant each time, what is the doubling time of the bacteria? Oa. 0.861 hr O b. 0.917 hr O c. 1.045 hr O d. 0.582 hr (y-3)/(x³+1) dy = y"dx is a separable differential equation. Select one: O True O False
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