In a growing industry, the mean number of hours of productivity lost by employees per week due to online social media engagement is 8 hours, with a standard deviation of 2 hours. Note: Assume the population data is normally distributed. a. What is the probability that an employee will lose more than 10 hours of productivity due to online social media engagement? P(X > 10)= Round to four decimal places if necessary b. What is the probability that 11 employees will lose more than 9 hours of productivity due to online social media engagement? P( X̄ > 9)=
In a growing industry, the mean number of hours of productivity lost by employees per week due to online social media engagement is 8 hours, with a standard deviation of 2 hours. Note: Assume the population data is normally distributed. a. What is the probability that an employee will lose more than 10 hours of productivity due to online social media engagement? P(X > 10)= Round to four decimal places if necessary b. What is the probability that 11 employees will lose more than 9 hours of productivity due to online social media engagement? P( X̄ > 9)=
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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In a growing industry, the mean number of hours of productivity lost by employees per week due to online social media engagement is 8 hours, with a standard deviation of 2 hours.
Note: Assume the population data is normally distributed.
a. What is the probability that an employee will lose more than 10 hours of productivity due to online social media engagement?
P(X > 10)=
Round to four decimal places if necessary
b. What is the probability that 11 employees will lose more than 9 hours of productivity due to online social media engagement?
P( X̄ > 9)=
Round to four decimal places if necessary
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