In a food preference experiment, 80 lizards were given the opportunity to choose to eat one of three different species of insects. The results showed that 33 of the lizards chose species A, 12 chose species B, and 35 chose species C. They conducted a Chi- squared analysis to test for equal preference. They obtained a X calculated 15.12, and an X critical - 5.991. Write a conclusion for this test. Do not just say "Reject" or "Do Not Reject". Your conclusion must say something about the lizards' preference.

About 4% of the population has a particular genetic mutation. 300 people are randomly selected.Find the mean for the number of people with the genetic mutation in such groups of 300. (Remember that means should be rounded to one more decimal place than the raw data.)

In a survey, 37% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result to be too high, so he randomly selected 200 pet owners and discovered that 73 of them spoke to their pet on the telephone. Does the veterinarian have a right to be skeptical? Use the a = 0.1 level of significance. Because npo (1- Po) 10, the sample size is 5% of the population size, and the sample the requirements for testing the hypothesis satisfied. (Round to one decimal place as needed.) Enter your answer in the answer box and then click Check Answer. ? 4 parts remaining Clear All Check Answer Screen Shot 202...png Show All

A researcher would like to know which factors are most important to people who are buying a new car. A sample of n=200 customers between the ages of 20 and 29 are asked to identify the most important factor in the decision process: Performance, Reliability, or Style. The researcher would like to know whether there is a difference between the factors identified by women compared to those identified by men. The data are as follows:  Observed Frequencies of Most Important Factors According to Gender:   Performance Reliability Style Total Male 21 33 26 80 Female 19 67 34 120 Total 40 100 60   Compute the expected frequencies (fill in chart). Expected Frequencies:   Performance Reliability Style Male       Female

A study was conducted to determine the proportion of people who dream in black and white instead of color. Among 323 people over the age of​ 55, 71 dream in black and​ white, and among 288 people under the age of​ 25, 14 dream in black and white. Use a 0.05 significance level to test the claim that the proportion of people over 55 who dream in black and white is greater than the proportion for those under 25. Complete parts​ (a) through​ (c) below.       Question content area bottom Part 1 a. Test the claim using a hypothesis test.   Consider the first sample to be the sample of people over the age of 55 and the second sample to be the sample of people under the age of 25. What are the null and alternative hypotheses for the hypothesis​ test?     A. H0​: p1=p2 H1​: p1<p2   B. H0​: p1≥p2 H1​: p1≠p2   C. H0​: p1≠p2 H1​: p1=p2   D. H0​: p1≤p2 H1​: p1≠p2   E. H0​: p1=p2 H1​: p1>p2 Your answer is correct.   F. H0​: p1=p2 H1​:…

Answer j and k

A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point Likert-type response in which 1 designated "not important" and 6 designated "extremely important." A random sample of n1 = 41 adults were asked about fishing as an outdoor activity. The mean response was x1 = 4.9. Another random sample of n2 = 50 adults were asked about camping as an outdoor activity. For this group, the mean response was x2 = 5.7. From previous studies, it is known that ?1 = 1.6 and ?2 = 1.5. Does this indicate a difference (either way) regarding preference for camping versus preference for fishing as an outdoor activity? Use a 5% level of significance.Note: A Likert scale usually has to do with approval of or agreement with a statement in a questionnaire. For example, respondents are asked to indicate whether they "strongly agree," "agree," "disagree," or "strongly disagree" with the statement. (a) What is the level of significance? .05   State the null and alternate…

An LED light bulb manufacturer claims that the average lifespan of its 60-watt LED light bulbs is 43,000 hours.A corporate watchdog group is suspicious of the company's claim and thinks that the true average lifespan of the 60-watt LED light bulbs produced by the company may be less than the advertised 43,000 hours. The group collected and tested a random sample of 240 light bulbs and found the average lifespan of the sample was 42,958 hours.Use the p-value method to test the hypothesis that the mean lifespan of this brand of 60-watt LED light bulb is less than 43,000 hours, using α=0.025α=0.025. Assume the standard deviation of the lifespan of all such light bulbs is known to be 430 hours.State the null and alternative hypothesis for this test.H0:H0:              H1:H1:              Determine if this test is left-tailed, right-tailed, or two-tailed. right-tailed two-tailed left-tailed Should the standard normal (zz) distribution or Student's (tt) distribution be used for this…