In a factorial experiment, Sergio studies the effects of different feed grains (corn, barley...) and feed supplements on cattle weight gain during a 6 month period.His experiment has 4 replications. During the experiment, two cattle died and resulted in 2 missing data points. Using the information in the below table, calculatethe adjusted Feal of Supplements (S), considering the missing data points. Round up to 2 decimalsSOVFeed (F)Supplement (S)FXSErrorTotaldf445SS892527961500MSFealHAYA 22WEXSHIMIKANTINGANAKAMAT

Answered: In a factorial experiment, Sergio…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Kris works for the MESA Air Pollution Study at UW, and studies the correlation be- tween air pollution and the disease atherosclerosis. Nationally, 40% of adults suffer from atherosclerosis. Kris suspects that the proportion of people with atherosclerosis in high- pollution areas is higher. In a random sample of 600 residents of high-pollution areas, he finds that 270 (45%) subjects have atherosclerosis. At the 1% level (α = .01), is this good evidence that people in high-pollution areas are more likely to have atherosclerosis? (a) Which of the following is the Ha ? (research claim or alternate) A. Ha : p ≥ 0.40 B. Ha : pb ≥ 0.40 C. Ha : p > 0.40 D. Ha : p > b 0.40 E. Ha : p > b 0.45 F. Ha : p > 0.45 G. Ha : pb ≥ 0.45 H. Ha : p ≥ 0.45 I. None of these Hint: First read the problem and using my notes (or Hawkes) for 9.1, set up H0 and Ha . Then pick the right Ha from the above list. Dont try to guess the answer from the above list. (b) Which of the…
Fish of Lake Laengelmaevesi. An article by J. Puranen of the Department of Statistics, University of Helsinki, discussed a classic study on several variables of seven different species of fish caught in Lake Laengelmaevesi, Finland. On theWeissStats site, we present the data on weight (in grams) and length (in centimeters) from the nose to the beginning of the tail for four of the seven species. Perform the required parts for both the weight and length data. a. Obtain individual normal probability plots and the standard deviations of the samples. b. Perform a residual analysis. c. Use your results from parts (a) and (b) to decide whether conducting a one-way ANOVA test on the data is reasonable. If so, also do parts (d) and (e). d. Use a one-way ANOVA test to decide, at the 5% significance level, whether the data provide sufficient evidence to conclude that a difference exists among the means of the populations from which the samples were taken. e. Interpret your results from part (d)
A sample of 150 matched pairs of banks was formed in a study comparing banks in Turkey and Germany. Each pair contained one bank from Turkey and one from Germany. The pairings were made in such a way that the two members were as similar as possible in regard to such factors as size and age. The ratio of total loans outstanding to total assets was calculated for each of the banks. For this ratio, the sample mean difference (Turkey - Germany) was 0.0412, and the sample standard deviation of the differences was 0.3039. Test, against a two-sided alternative, the null hypothesis that the two population means are equal. (Assume a = 0.01.) Click the icon to view the critical values of the Student's t distribution. Which of the following cor greater than tn-1, a/2 O B. Ho: Hx - Hy = 0 0< 1 - *rt :H O A. Ho: Hx -Hy =0 greater than - tn - 1, a 0# 서-저 : H O D. Ho: Hx-Hy = 0 OC. Ho: Hx-Hy #0 H: Hx-Hy =0 greater than t,-1. g 05 1 - Xt :'H less than -tn-1, a O F. Ho: Hx - Hy = 0 O E. Ho: Hx -Hy =0…
In a study comparing banks in two countries, a sample of 142 matched pairs of banks was formed. Each pair contained one bank from country x and one from country y. The pairings were made in such a way that the two members were as similar as possible in regard to such factors as size and age. The ratio of total loans outstanding to total assets was calculated for each of the banks. For this ratio, the sample mean difference (country x - country y) was 0.0579, and the sample standard deviation of the differences was 0.3086. Test, against a two-sided alternative, the null hypothesis that the two population means are equal. (Assume α = 0.01.) Click the icon to view the critical values of the Student's t distribution. Which of the following correctly states Ho and H₁ ? A. Ho: Mx Hy = 0 H₁: Hx-Hy >0 OC. Ho: Mx Hy ‡0 Hi HxHy=0 - O E. Ho: Mx Hy = 0 H₁: Hx-Hy <0 B. Ho: Mx Hy = 0 H₁: Hx-Hy #0 D. Ho: Hx-Hy = 0 H₁: Hx-Hy 20 OF. Ho: Mx Hy = = 0 H₁: Hx-Hy ≤0
In a study comparing banks in two countries, a sample of 142 matched pairs of banks was formed. Each pair contained one bank from country x and one from country y. The pairings were made in such a way that the two members were as similar as possible in regard to such factors as size and age. The ratio of total loans outstanding to total assets was calculated for each of the banks. For this ratio, the sample mean difference (country x - country y) was 0.0579, and the sample standard deviation of the differences was 0.3086. Test, against a two-sided alternative, the null hypothesis that the two population means are equal. (Assume α = 0.01.) Click the icon to view the critical values of the Student's t distribution. The test statistic is t = 2.236. (Round to three decimal places as needed.) The critical value(s) is(are) (Round to three decimal places as needed. Use a comma to separate answers as needed.)
A doctor in Oklahoma City wants to know whether the average life span for heart disease patients at four hospitals in the city differ. The data below represents the life span, in years, of heart disease patients from each hospital. Perform an ANOVA test with a 10% level of significance to test whether the average life span of heart disease patients in Oklahoma City differs depending on the hospital that treats them Life Span of Patients Treated at Hospital 1: 8.1, 1.2, 7, 11.5, 21, 2, 15.3, 19.2, 10.5, 15.4, 12.7, 15.3, 12.1, 7.5, 11.4, 16.4, 26.7, 14.6, 1.5, 16.3, 12.6, 0.8, 18.2, 4.2, 9.6, 21, 16.3, 2.7 Life Span of Patients Treated at Hospital 2: 17.6, 11.6, 16.8, 5.2, 6.7, 3.2, 13.8, 12.5, 0.9, 6, 14.3, 1.8, 14.8, 10, 5.8, 15.2, 10, 3.7, 11.4, 21.6, 12.9, 0.5, 9.2, 13.9, 10.9 ▼ Part 1 of 4 Life Span of Patients Treated at Hospital 3: 8.5, 2.3, 11, 7.4, 14.8, 5.8, 11, 3.4, 10.9, 1.1, 5.9, 21.6, 12.5, 0.1, 15.5, 15.4, 0.8, 7.7, 5.6, 12, 7.1 Life Span of Patients Treated at Hospital…
determine whether suicide and homicide rates in metropolitan areas around the country are correlated. a sample of 10 metropolitan areas with their rates (number per 100,000), of suicide and homicide. computed the correlation coefficient of 0.70.
A biologist wants to determine if different temperatures (15oC, 25oC, or 35oC) and amounts of sunlight (partial or full) will affect the growth of plants. He will test each combination of temperature and sunlight by randomly assigning 15 plants to each of the combinations. What type of sampling is described in this study? one sample paired data two samples more than two samples
The data in the attached image represents blood pressure based on a new trial medication used in an experiment involving a total of 50 male and female subjects. There were two levels of treatment: 0 = placebo and 1 = treatment group. Family History Blood Pressure = Fam-Hist-BP; from the paternal side = PS; from the maternal side = MS; from both sides = BS; none on both sides or not known = N.; Blood pressure before the experiment = BP-Before-Exp; Blood pressure after the experiment = BP-After-Exp. Task: Construct a histogram to represent the family BP history, the subjects' BP before treatment and the subjects' BP after treatment.
3, 5, 5, 4, 2, 2, 1, 1, 1, 4, 5, 3, 3 calculate variance

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