In 2008, the per capita consumption of soft drinks in Country A was reported to be 18.11 gallons. Assume that the per capita consumption of soft drinks in Country A is approximately normally distributed, with a mean of 18.11 gallons and a standard deviation of 5 gallons. Complete parts (a) through (d) below. a. What is the probability that someone in Country A consumed more than 10 gallons of soft drinks in 2008? The probability is 0.9476 (Round to four decimal places as needed.) b. What is the probability that someone in Country A consumed between 3 and 5 gallons of soft drinks in 2008? The probability is .0031 (Round to four decimal places as needed.) c. What is the probability that someone in Country A consumed less than 5 gallons of soft drinks in 2008? The probability is 0044 (Round to four decimal places as needed.) d. 98% of the people in Country A consumed less than how many gallons of soft drinks? ng The probability is 98% that someone in Country A consumed less than gallons of soft drinks. (Round to two decimal places as needed.)

Q: 3 cot2 0-4 csc 0 = 1

Q: find sec 3% cot t 1TT Csc - T

Q: Evaluate. Use a capital C for any constant. 14(6z - 1) (62 - 2z - 1)° da %3D |

Q: Find d dx (45x+6)

Q: -2 Evaluate (5х — 2) dx -6

Q: 6x 4x 7x + 40 Compute 7. O6+ 80 + C O 3x + 4x - 7In]x| + 40 + C O 18x+ 8x - 7 +C 2x O 3x + 4x-7in|x|…

Q: 2 2 -2 If A = = -1 0 3 -4 -4 and B -2 0 th 1 -3 3A – 2B and 4AT 24

Q: .5 S Ix – 2| dz

Q: dr I4 +3

Q: 3 5 - Let C= 2 6 |. Find - 5C. - 1

Q: 3 Let A = 6 7 8 = ; and C = [1 -1 15. B 2 1 - Evaluate the following, if possible: (а) АС + В — (b)…

Q: 6. 3 3 Let A= -4 1 and C= -5 0 3 -2 -1 Find A+ C.

Q: Given: Prove: ZR and ZV are right Zs RT VT ARST AVST

Q: 5s – 6 Find L s² – 4s + 7.