IMPROVEMENT WITH RADIATION SHIELD. A shield having an emissivity of 0.1 Example 8.13 is placed around the thermometer in Example 8.12 such that the area ratio A/A, is 0.3. The temperature indicated by the thermometer under these conditions is 5°C. The convection heat- transfer coefficient is assumed to be the same, and the shield may be assumed essentiallv to surround the thermometer. Calculate the true air temperature under these circumstances. And find estimate its uncertainty? , = 0.1, A h = 10 W/m2-C E= 0.9, 0.3, T, = 273 +5 278 K, T, = 263 K %3D %3D %3D A,

IMPROVEMENT WITH RADIATION SHIELD. A shield having an emissivity of 0.1 Example 8.13 is placed around the thermometer in Example 8.12 such that the area ratio A/A, is 0.3. The temperature indicated by the thermometer under these conditions is 5°C. The convection heat- transfer coefficient is assumed to be the same, and the shield may be assumed essentiallv to surround the thermometer. Calculate the true air temperature under these circumstances. And find estimate its uncertainty? , = 0.1, A h = 10 W/m2-C E= 0.9, 0.3, T, = 273 +5 278 K, T, = 263 K %3D %3D %3D A,

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter1: Basic Modes Of Heat Transfer

Section: Chapter Questions

Problem 1.15P: 1.15 A thermocouple (0.8-mm-diameter wire) used to measure the temperature of the quiescent gas in a...

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Question

IMPROVEMENT WITH RADIATION SHIELD.
A shield having an emissivity of 0.1
Example 8.13
is placed around the thermometer in Example 8.12 such that the area ratio A/A, is 0.3. The
temperature indicated by the thermometer under these conditions is 5°C. The convection heat-
transfer coefficient is assumed to be the same, and the shield may be assumed essentiallv to
surround the thermometer. Calculate the true air temperature under these circumstances. And find estimate
its uncertainty?
h = 10 W/m - °C
E, = 0.1,
A
= 0.3,
A,
E = 0.9,
T, = 273 +5 = 278 K,
T, = 263 K

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IMPROVEMENT WITH RADIATION SHIELD. A shield having an emissivity of 0.1 Example 8.13 is placed around the thermometer in Example 8.12 such that the area ratio A/A, is 0.3. The temperature indicated by the thermometer under these conditions is 5°C. The convection heat- transfer coefficient is assumed to be the same, and the shield may be assumed essentially to surround the thermometer. Calculate the true air temperature under these circumstances. And estimate its uncertainty E, = 0.1, A = 0.3, A, € = 0.9, h = 10 W/m2 - °C T, = 273 +5 = 278 K, T, = 263 K
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