Improper integrals arise in polar coordinates when the radial coordinater becomes arbitrarily large. Under certain conditions, these integrals are treated in the usual way shown below. B 00 B b SS g(r,0)rdrde = lim SS9(r.0rdrde b→∞ a a Use the given technique to evaluate the following integral. ffe -x2-y²dA; R=((r.0): 1≤r<∞0,0 ≤0≤x} R SS₁²x²-x²= R (Type an exact answer, using as needed.)

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter7: Integration
Section7.5: The Area Between Two Curves
Problem 26E: Find the area between the curves in Exercises 1-28. x=0, x=/4, y=sec2x, y=sin2x
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Improper integrals arise in polar coordinates when the radial coordinate r becomes arbitrarily large. Under certain conditions, these integrals are treated in the usual way shown below.
ß ∞
ß b
Sfgr,0)r
JJ gr.
α a
α a
= lim
b→∞
g(r,0)rdrde:
g(r,0)rdrde
Use the given technique to evaluate the following integral.
S Se-x² - y² dA; R= {(1,0): 1 ≤r<∞0,0 ≤0 ≤t}
е
R
S Se
√√₁x²-xdA=D
е
R
(Type an exact answer, using as needed.)
Transcribed Image Text:Improper integrals arise in polar coordinates when the radial coordinate r becomes arbitrarily large. Under certain conditions, these integrals are treated in the usual way shown below. ß ∞ ß b Sfgr,0)r JJ gr. α a α a = lim b→∞ g(r,0)rdrde: g(r,0)rdrde Use the given technique to evaluate the following integral. S Se-x² - y² dA; R= {(1,0): 1 ≤r<∞0,0 ≤0 ≤t} е R S Se √√₁x²-xdA=D е R (Type an exact answer, using as needed.)
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