import numpy as np def integer_to_binary(a,n=16): b=np.zeros(n,dtype=int) for i in range(n, -1, -1): x = 2**i if (a / x) >= 1: b[i]=1 a =a - x b=b[::-1] return b def decimal_to_binary(a,n=16): b=np.zeros(n,dtype=int) for i in range(1, n, 1): x = 2**(-1*i) if (a - x) >= 0: b[i]=1 a =a - x return b Using phyton I want to make  a new function float_to_binary(a,n) This method can be use for a integer_to_binary function and use for n  binary_to_integer function and  print that if I write float_to_binary(231.210)   for that  ( integer_to_binary(231), decimal_to_binary(210) ) and print the answer . Thanks so much I need to thıs for a 1 hour.       and  then  decimal_to_binary(210)

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Counting sort

The counting sort algorithm sorts an array’s contents by counting the repetition of each element that occurs in the array. A counting sort algorithm is a stable algorithm that works the best when the range of elements in the array is small, say for example from 0 to 9. The count which is the number of repetitions of an element in the array is mapped to an index of an auxiliary array, which is then saved in an auxiliary array. The counting sort algorithm has a stable time complexity of the order of O(size of array + size of auxiliary array). Let’s discuss the algorithm in detail as follows.