Imagine that your null hypothesis is σ2 = 10 and your alternative hypothesis is σ2 > 10. What is the critical value for the test statistic  given α = 0.05 and n = 12?

Under what circumstances is a t statistic used instead of a z-score for a hypothesis test?     Justin wants to know whether a commonly prescribed drug does improve the attention span of students with attention deficit disorder (ADD). He knows that the mean attention span for students with ADD who are not taking the drug is 2.3 minutes long. His sample of 12 students taking the drug yielded a mean of 4.6 minutes. Justin can find no information regarding σx , so he calculated s2x =1.96. Determine the critical region using a one-tailed test with alpha = .05. Conduct the hypothesis test (Do the math and compare the t-critical and t-obtained values). State your conclusions in terms of H0 (Should you reject the H0 or fail to reject/accept the H0). Based on your analysis, is there a relationship between the drug and attention span?

Only 15% of registered voters voted in the last election. Will voter participation increase for the upcoming election? Of the 363 randomly selected registered voters surveyed, 58 of them will vote in the upcoming election. What can be concluded at the αα = 0.01 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion  The null and alternative hypotheses would be:       H0:H0:  ? μ p  Select an answer > < ≠ =  (please enter a decimal)     H1:H1:  ? μ p  Select an answer = < ≠ >  (Please enter a decimal) The test statistic ? t z  = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤  αα Based on this, we should Select an answer accept reject fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly higher than 15% at αα = 0.01, so there…

Suppose the national average dollar amount for an automobile insurance claim is $777.86. You work for an agency in Michigan and you are interested in whether or not the state average is less than the national average. The hypotheses for this scenario are as follows: Null Hypothesis: μ ≥ 777.86, Alternative Hypothesis: μ < 777.86. You take a random sample of claims and calculate a p-value of 0.0232 based on the data, what is the appropriate conclusion? Conclude at the 5% level of significance.   Question 9 options:   1)  The true average claim amount is significantly different from $777.86.   2)  The true average claim amount is significantly less than $777.86.   3)  The true average claim amount is significantly higher than $777.86.   4)  We did not find enough evidence to say the true average claim amount is less than $777.86.   5)  The true average claim…

Only 12% of registered voters voted in the last election. Will voter participation increase for the upcoming election? Of the 390 randomly selected registered voters surveyed, 62 of them will vote in the upcoming election. What can be concluded at the αα = 0.01 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion  The null and alternative hypotheses would be:       H0:H0:  ? p μ  Select an answer > < ≠ =   (please enter a decimal)     H1:H1:  ? p μ  Select an answer ≠ < = >   (Please enter a decimal) The test statistic ? z t  =  (please show your answer to 3 decimal places.) The p-value =  (Please show your answer to 4 decimal places.) The p-value is ? ≤ >  αα Based on this, we should Select an answer accept reject fail to reject  the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly higher than 12% at αα = 0.01, so…

Suppose there is a claim that a certain population has a mean, µ, that is different than 7. You want to test this claim. To do so, you collect a large random sample from the population and perform a hypothesis test at the 0.05 level of significance. To start this test, you write the null hypothesis H, and the alternative hypothesis H, as follows. Hoi u= 7 H: u =7 Suppose you also know the following information. The critical values are - 1.960 and 1.960 (rounded to 3 decimal places). The value of the test statistic is 2.477 (rounded to 3 decimal places). (a) Complete the steps below to show the rejection region(s) and the value of the test statistic for this test. Standard Normal Distribution Step 1: Select one-tailed or two-tailed. One-tailed 0.3 Two-tailed Step 2: Enter the critical value(s). (Round to 3 decimal places.) 0.2+ 0.1+ Step 3: Enter the test statistic. (Round to 3 decimal places.) 2 (b) Based on your answer to part (a), choose the correct statement. O The value of the test…

Suppose that we have a problem for which the null and alternative hypothesis are given by: H0: μ = 890. H1:μ ≠ 890. Is this a right-tailed test, left-tailed test, or two-tailed test. Find the z value based on a level of significance of α=.09.

What would be the critical value for a left-tailed test with α = 0.01? (Remember to use the z-score table)

According to a survey the percent of high school graduates is 69%. One city wanted to know if the proportion of high school graduates is different from the known national proportion. The city samples 150 citizens to know if the proportion of high school graduates and 98 are graduates. (10 points) State the null and alternative hypotheses. What is the value for the t-test for the proportion? For α = .05 (two-tailed) what is the appropriate p value?

Suppose there is a claim that a certain population has a mean, 4, that is different than 5. You want to test this claim. To do so, you collect a large random sample from the population and perform a hypothesis test at the 0.05 level of significance. To start this test, you write the null hypothesis H, and the alternative hypothesis H1 as follows. Ho: u=5 H: H=5 Suppose you also know the following information. The critical values are -1.960 and 1.960 (rounded to 3 decimal places). The value of the test statistic is 2.574 (rounded to 3 decimal places). (a) Complete the steps below to show the rejection region(s) and the value of the test statistic for this test. Standard Normal Distribution Step 1: Select one-tailed or two-tailed. One-tailed 0.3+ Two-tailed Step 2: Enter the critical value(s). (Round to 3 decimal places.) 0.2+ 0.1+ Step 3: Enter the test statistic. (Round to 3 decimal places.) ? (b) Based on your answer to part (a), choose the correct statement. The value of the test…